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SpyIntel [72]
2 years ago
7

Which function is shown in the graph below?

Mathematics
1 answer:
pishuonlain [190]2 years ago
8 0

Answer: c

Step-by-step explanation:

It has been given that the point (3,1) is on the graph.

And in order for the point (3,1) to lie on the graph, of all the given options the closest we can get is when we have Option C

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Use the following information for questions 1 through 6. The dietitian at a camp is planning breakfast for the first day of camp
Dima020 [189]

Answer:

Let x and y be the pieces of toast and sausage required.

Then the objective function is

Min Z=0.04x+0.08y

Constraints:

Vitamin A, 2x+4y≥20

Vitamin B, 3x+1.5y≥15

Iron, 2x+2y≥16

Sausage, y≤4

The non-negative constraints are x≥0, y≥0

Thus, the linear programming model is

Min Z=0.04x+0.08y

Subject to,

2x+4y≥20

3x+1.5y≥15

2x+2y≥16

y≤4

x≥0, y≥0

1) There are two variables in the LP model. So, option (B) is correct.

2) The LP model contains four constraints (excluding the non negative constraints). So, option (D) is correct.

3) Solving the LP model using a software, we get the solution as

z=0.4, at x=6 and y=2

So, The cost of the breakfast is $ 0.4. Option (B) is correct.

4) The breakfast should contains 6 toasts.

5) The amount of Vitamin B in the breakfast = 3(6)+1.5(2)=18+3=21 milligrams. So, option (C) is correct.

6) The amount of Iron in the breakfast= 2(6)+2(2)=12+4=16 milligrams. So, option (B) is correct.

Step-by-step explanation:

4 0
3 years ago
If VT=2,what is the length of PT?
marusya05 [52]

Step-by-step explanation:

\underline{ \underline{ \text{Given : }}}

  • Perpendicular ( P ) = VT = 2
  • Base ( b ) = PT
  • \theta =  \tt{60 \degree}

\underline{ \underline{ \text{Solution}}} :

\tt{ \tan(60 \degree)  =  \frac{perpendicualar}{base}}

⟶ \tt{ \sqrt{3}  =  \frac{2}{PT}}

⟶ \tt{ \sqrt{3}  \: PT= 2}

⟶ \tt{PT =  \frac{2}{ \sqrt{3}} }

⟶ \tt{PT= \boxed{\tt{ \frac{2 \sqrt{3} }{{3} }}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
3 years ago
Help me i beg u plzzzz
Ainat [17]
We can say at month 0 she was 43 inches tall.

And at month 18 she was 52 inches tall.

We can say that x is the number of months and y is her height.

Rise/run
y2-y1/x2-x1
52-43/18-0
9/18
1/2

So the slope is 1/2 (which is what you are looking for.) and if you were to write an equation it would be y=1/2x+43

Brainliest my answer if it helps you out?
5 0
3 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
3 years ago
Which is a solution to the system of inequalities? y≤-1/2x+3 y≥x+1
Serggg [28]

Answer:

y≤-1/2(x=4)+3

Step-by-step explanation:

4 0
3 years ago
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