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taurus [48]
4 years ago
9

Lim x>-1 x^2-x-2/x+1

Mathematics
1 answer:
antiseptic1488 [7]4 years ago
7 0

Answer:

-3

Step-by-step explanation:

If we directly evaluate the function at -1, we get 0/0, meaning we may still have a limit to find.

In this case, factoring the polynomial at the top would be helpful.

The polynomial can be factored to (x+1)(x-2), so the function would now turn out to be (x+1)(x-2)/(x+1)

The (x+1) cancel out, leaving you with (x-2), which you can directly evaluate by plugging in x as -1:

-1-2 = -3

Quick disclaimer: the function is still undefined at -1; it's just that the function gets closer and closer to -3 as you approach -1.

I hope this helped you.

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Line A passes through the coordinate points (-2/5,0) and (0,1). Which of the following lines will line A never intersect? ​
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Answer:

Option B

Step-by-step explanation:

Only lines which are parallel to the line which connects the given two points will neve r intersect,

parallel line has same slope

the slope of the line which connects the given two points is, 5/2

and the line is option B also has the same slope, so those two lines will never intersect each other.

Answered by GAUTHMATH

4 0
3 years ago
Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni
IRINA_888 [86]
So18 is to 2 and54 is to 6
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3 0
4 years ago
The base of a solid in the xy-plane is the first-quadrant region bounded y = x and y = x^2. Cross sections of the solid perpendi
musickatia [10]
Check the picture below.

thus, if one side on the square is x - x², then the area for the square is (x - x²)(x - x²), or (x - x²)²

now... what is the "x" value for the region, let's check their intersection.

\bf \begin{cases}
y=x\\
y=x^2
\end{cases}\implies x=x^2\implies 0=x^2-x\implies 0=x(x-1)
\\\\\\
x=
\begin{cases}
0\\
1
\end{cases}\\\\
-------------------------------\\\\
\displaystyle \int\limits_{0}^{1}\ (x-x^2)^2\cdot dx\implies \int\limits_{0}^{1}\ (x^2-2x^3+x^4)\cdot dx
\\\\\\
\cfrac{x^2}{2}-\cfrac{2x^4}{4}+\cfrac{x^5}{5}\implies \left. \cfrac{x^2}{2}-\cfrac{x^4}{2}+\cfrac{x^5}{5} \right]_{0}^{1}\implies \left[ \cfrac{1}{2}-\cfrac{1}{2}+\cfrac{1}{5} \right]-[0]\implies \cfrac{1}{5}

4 0
3 years ago
Read 2 more answers
The sides of this rectangle are marked off in centimeters. If the rectangle is enlarged proportionally so that the longer side i
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the length of the shorter side is:L  = 13.125cm

<h3>how long will the shorter side be?</h3>

In the longer side we have 8 segments.

We know that the side measures 35 cm, then each one of the 8 segments measures:

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Now, we can see that in the shorter side we have 3 of these segments.

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If you want to learn more about lengths:

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4 0
2 years ago
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