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Mashcka [7]
2 years ago
15

Are these numbers rational or irrational? √10 (square root of 10) √16 (square root of 16) 52% 1.235 1. Rational 2. Irrational pl

ease answer fast this needs to be in before tomorrow​

Mathematics
1 answer:
77julia77 [94]2 years ago
5 0

Step-by-step explanation:

any rational number can be expressed as a/b, with a and b being integer numbers, and b different to 0.

-7 = -7/1 rational

sqrt(10) irrational (because there is no rational number multiplied by itself that results in 10)

sqrt(16) = sqrt(4×4) = 4 = 4/1 rational

52% = 52/100 rational

1.235 = 1235/1000 rational

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4 years ago
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The faces of a triangular pyramid have a base of 5 cm and height of 11 cm. What is the lateral area of the pyramid?
horrorfan [7]
I think 55 because you would multiply 11×5
7 0
3 years ago
50 POINTS
Marina86 [1]

vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.

Givens

vi = 160 ft/s

vf = 0 (the rocket stops at the maximum height.)

a = - 9.81 m/s

t = ????

Remark

YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.

Equation

a = (vf - vi)/t

Solve

- 32 = (0 - 160)/t Multiply both sides by t

-32 * t = - 160 Divide by -32

t = - 160/-32

t = 5

You will also need to solve for the height to answer part B

t = 5

vi = 160 m/s

a = - 32

d = ???

d = vi*t + 1/2 a t^2

d = 160*5 + 1/2 * - 32 * 5^2

d = 800 - 400

d = 400 feet

Part B

You are at the maximum height. vi is 0 this time because you are starting to descend.

vi = 0

a = 32 m/s^2

d = 400 feet

t = ??

formula

d = vi*t + 1/2 a t^2

400 = 0 + 1/2 * 32 * t^2

400 = 16 * t^2

400/16 = t^2

t^2 = 25

t = 5 sec

The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.

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4 years ago
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During the mayoral election,two debates were held between the canidates. The first debate lasted 1 4/5 hours. The second one las
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Answer:

3\frac {6}{25} hrs \ or \ 3 hrs\  14 mins \ 24 sec

Step-by-step explanation:

The question calls requires one to get the product of the given time. Since first debate lasted for :

1\frac {4}{5} \ hrs

-and the second lasted

1\frac {4}{5} hrs times more than the first then the second took then the first step will involve converting the mixed fractions into improper fraction which will be:

\frac {9}{5}

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\frac {9}{5}\times\frac{9}{5}\\\\=\frac{81}{25}=3\frac{6}{25}hrs

5 0
3 years ago
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