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3 years ago

I need to simplify √(5+2√2) and √(6+2√5)

1 answer:

6 0

This expression is easier than it looks like. I thought that to solve it you have for example to express the 2 via 10 * 5^-1 and stuff like that - but you can multiply and divide this expression by some factor. In our case first we multiply by conjunctive expression root(5-2root2) and the second by root(6+2root5). In first we get root16 and the second calculate.

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P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball

Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 30, p = 0.626$

$\mu = E(X) = np = 30*0.626 = 18.78$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65$

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is $P(X \leq 16 + 0.5) = P(X \leq 16.5)$ , which is the pvalue of Z when X = 16.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{16.5 - 18.78}{2.65}$

$Z = -0.86$

$Z = -0.86$ has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0

3 years ago

Sam bought a soda and a bag of chips for $3. If the soda cost $1.75, how much was the bag of chips?

Anarel [89]

Answer:

1.25

Step-by-step explanation:

The bag of chips is worth the same as the entire purchase minus the soda.

Therefore the chips are worth 3 - 1.75 = 1.25

3 0

4 years ago

Read 2 more answers

For an outdoor concert by the city orchestra, concert organizers estimate that 19 comma 000 people will attend if it is not rai

Amiraneli [1.4K]

Answer:

14,800 people are expected to attend the concert

Step-by-step explanation:

In this question, we are tasked with calculating the expected number of people that will attend a concert on a particular day.

The key to answering this question is to multiply the individual probabilities of the two events by the expected number of people

Mathematically, what we obtain is the following;

The expected number of people at the concert = (probability of raining × expected number of people when it rains) + (probability of not raining × Expected number of people when it does not rain)

From the question, we identify that;

Probability of raining = 30% = 30/100 = 0.3

Probability of not raining = 1-probability of raining = 1-0.3 = 0.7

Expected number of people when it rains = 5,000

Expected number of people when there is no rain = 19,000

we plus these vales into the equation we have;

The expected number of people at the concert =( 0.3 × 5,000) + (0.7 × 19,000) = 1,500 + 13,300 = 14,800 people

6 0

4 years ago

Help asap, please!!!!!!!!

Artemon [7]

1/6p + (-4/5) is the equivalent expression. You have to add like terms, meaning constants are added to constants, variables are added to variables, etc. the result you get from adding like variables leaves you with 1/6p + (-4/5) or 1/6p - 4/5

8 0

3 years ago

A group of fitness club members lose a combined total of 28 kilograms in 1 week. There are approximately 2.2 pounds in 1 kilogra

marissa [1.9K]

Answer: 12.32 for 5 day week or 8.8 for a seven day week

Step-by-step explanation:

2.2 x 28 = 61.6

61.6 divided by 5 is 12.32

divide by seven if its a full week and the answer is 8.8

7 0

3 years ago