7y^2 + 10y + 3
7y^2 + 7y + 3y + 3
(7y^2+7y) + (3y+3)
7y(y+1) + 3(y+1)
(7y+3)(y+1)
So the final answer is <span>(7y+3)(y+1)</span>
To add them, you first need a common denominator.
So multiply <span> 1/4 by 5/5 and 1/5 by 4/4 first.
Now they'll be 5/20 and 4/20.
Add them to get 9/20. </span>
First you multiply 6(x) then you multiple 6(8)
Your equation should now look like this: 6x-48=72
Subtract 48 from both sides
Your equation should now look like 6x=120
Divide by 6
Answer is 20
Answer:
The answer is: 13 minutes
Step-by-step explanation:
First Let us form equations with the statements in the two scenario
Let the time in which the bell rings be 'x'
1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes
2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

Next, collecting like terms:

dividing both sides by 3:
x = 390÷30 = 13
∴ x = 13 minutes
Answer:
1680
Step-by-step explanation:
12+7+6=25
12+20*12=252
20+20+7=47
7*20*12=1680