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777dan777 [17]
3 years ago
8

Betty makes an 8% commission on any artwork she sells. If she sells $125 worth of artwork, how much is her commission?

Mathematics
1 answer:
horsena [70]3 years ago
5 0

Answer:

$10

Step-by-step explanation:

125x.08= $10

hope it helps:)

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Find parametric equations for the line. (Use the parameter t.) The line through the origin and the point (2, 6, −1) (x(t), y(t),
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5

Step-by-step explanation:

i think its 2 with the remainder of 8

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How can you establish credit?
Alex_Xolod [135]

Answer:

c pay bills on time using credit

Step-by-step explanation:

6 0
3 years ago
Describe two different strategies you could use to solve 16+35+24+14
kap26 [50]

16 + 35 + 24 + 14 = 51+ 38 = 89
16 + 35 + 24 + 14 = 16 + 59 + 14 = 75 + 14 = 89
3 0
3 years ago
A car, originally valued at 70,000 in 2006 depreciates exponentially at a rate of 4% each year. Round the expected value of the
lora16 [44]

Answer:

$42,890

Step-by-step explanation:

The standard form for an exponential equation is

y=a(b)^x

where a is the initial amount value and b is the growth rate or decay rate and t is the time in years.  Since we are dealing with money amounts AND this is a decay problem, we can rewrite accordingly:

A(t)=a(1-r)^t

where A(t) is the amount after the depreciation occurs, r is the interest rate in decimal form, and t is the time in years.  We know the initial amount (70,000) and the interest rate (.04), but we need to figure out what t is.  If the car was bought in 2006 and we want its value in 2018, a total o 12 years has gone by.  Therefore, our equation becomes:

A(t)=70,000(1-.04)^{12} or, after some simplification:

A(t)=70,000(.96)^{12}

First rais .96 to the 12th power to get

A(t) = 70,000(.6127097573)

and then multiply.

A(t) = $42,890

8 0
3 years ago
Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard de
Agata [3.3K]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

In point A:

\to df = n - 1 = 71-1= 70

In point B:

\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to  13.335315832 = (x - 81)\\\\\to  13.335315832 +81 =x \\\\\to x= 94.335315832

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816

In point F:

The lower cutoff is 0.90 in the center, which would be around 80 %. The critical point therefore is

tcrit = 1.293762898

\to 1.293762898 = \frac{(x-81)}{8}\\\\\to 1.293762898 \times 8= x-81\\\\\to 10.350103184 =x-81\\\\\to 10.350103184 +81=x\\\\\to x = 91.350103184\\

5 0
3 years ago
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