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2 years ago

J is the midpoint of

Mathematics

1 answer:

Mama L [17]2 years ago

3 0

4) reflexive property

5) SSS

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Jordan has $55 she earns $67 by doing chores how many money does Jordan have now

scZoUnD [109]

$122 because if you add 55 + 67 you get 122 then you just add the dollar sign

4 0

3 years ago

Read 2 more answers

Whats the domain of f(x)=x^2+6x-3

pickupchik [31]

Hello!!

The domain of any polynomial expression is all real numbers from -infinity to +infinity. This is due to the leading x^2 term!

Hope this helps you understand! Thank you!!

3 0

3 years ago

What is the inverse to 2^x-1

nydimaria [60]

Replace x with y and solve for y~

y=2*

x=2^y

log x = y log 2

y=log x / log 2

Hope this helps and leave a brainliest to help me reach expert ;)

4 0

3 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

4 years ago

What is the slope of the line passing through the points (-3, 4) and (2, - 1)? A -1

Serggg [28]

Answer:

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 3, 4 ) and (x₂, y₂ ) = (2, - 1 )

m = $\frac{-1-4}{2-(-3)}$ = $\frac{-5}{2+3}$ = $\frac{-5}{5}$ = - 1 → A

3 0

3 years ago