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AysviL [449]
3 years ago
12

WILL NAME BRAINLIEST WHOEVER CAN HELP ME FIRST! PLEASE I NEED A REAL ANSWER!! A quadrilateral is graphed on a coordinate plane.

If the vertices are A(2, 6), B(6, 0), C(2, –6) and D(–4, 0), which two points are farthest apart? A. A and B B. B and D C. A and C D. C and D
Mathematics
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

A(2, 6) and C(2, -6)

Step-by-step explanation:

The distance between any two points is given by :

Given vertices : A(2, 6), B(6, 0), C(2, -6) and D(-4, 0)

Since, points A and C has the largest distance between them.

Therefore, the points A and C are the farthest points.

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irakobra [83]

Step-by-step explanation:

Given that,

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\longmapsto\rm{7 \; cm =  r }\\

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\longmapsto\bf{Diameter = 14 \; cm}\\

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nasty-shy [4]

Answer:

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To complete the square, the last term has to be 1. So adding 10 to both sides, we get:

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Since 4z^2+4z+1=(2z+1)^2,

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On a number line, suppose point E has a coordinate of 4, and EG = 11. What are the possible coordinates of point G?
navik [9.2K]

Answer:

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Step-by-step explanation:

The positive difference between E and G is 11.

<h3>Solution</h3>

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Possible coordinates for G are -7 and 15.

4 0
2 years ago
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