Answer:
Protein B has a higher affinity for ligand C than protein A
Explanation:
Binding affinity is a measure of the strength of the bonds or interactions between a single biomolecule or receptor to its ligand. A ligand is usually a small molecule that binds to a specific receptor.
The receptor is usually a large molecule that contains a specific site for the binding of ligand.
Binding affinity is usually measured by the equilibrium dissociation constant (KD). The equilibrium dissociation constant KD is a ratio of the dissociation and the association of ligand to the receptor. The value of KD is used to evaluate and compare the strengths of bimolecular interactions. The larger the KD value, the more weakly the target molecule and ligand are attracted to and bind to one another.
The higher the dissociation constant (KD), the weaker the affinity is between the interacting molecules, whereas, the smaller the KD value, the greater the binding affinity of the ligand for its target.
Protein B has a KD value of 10⁻⁹ M while Protein A has a KD of 10⁻⁶ M.
Ration of KD of protein B to protein A = 10⁻⁹ M/10⁻⁶ M = 10⁻³
Therefore, protein B has a KD value which is 1000 times smaller than the KD of protein A.
I think the correct answer from the choices listed above is option D. Modern fishing practices threaten biodiversity mainly through the removal of community food supplies. When people remove a significant amount of fish, portions of the food web are disturbed and can affect a certain ecosystem.
I Know It has to be the stomach
A. All biomes not dominated by trees typically exhibit considerable seasonality in <span>either temperature, precipitation, or both
</span><span>A biome is composed of various diverging ecosystems that relates with the community. Biomes can either be deserts, grassland, savanna, tropical rain forest, taiga, boreal and etc.</span>
