<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
a(7)=3645
Step-by-step explanation:
you have :
f(1) =a= 5
and from recursive rule: f(n) = r · f(n − 1) and f(n) = 3 · f(n − 1)
So r=3
then
a(n)=a*r^(n-1)
a(7)=5*3^(7-1)
a(7)=5*3^6=3645
<em>hope this helps</em>
<em />
Decreasing then increasing, y goes down then y goes back up
For question 13, you need to look at all the numbers that are less than 1/2 and then count the number of marks in total .
Answer: 7 B
For question 14, you need to first make an equation that suits the circumstances and the situations in this problem.
$25+$24x=$193
$24x=$168
x=7 weeks
x stands for the number of weeks that she has to wait for in order to save enough money to purchase the camera.
Answer: 7 weeks A
