3y = 2x + 6
x + y = 7
y = 7 - x
3(7 - x) = 2x + 6
21 - 3x = 2x + 6
21 - 6 = 2x + 3x
15 = 5x
15/5 = x
3 = x
x + y = 7
3 + y = 7
y = 7 - 3
y = 4
Solution is (3,4)
Answer:
21 & 22
42.25 ÷ 2 = 21.125.
21.125 rounded to the two nearest whole numbers is 21 and 22.
21 and 22 are the closest integers to 21.125.
The answer is 21 and 22.
Hope it helps!
You need to know the base to answer this. but if you want i will explain it divide 62.4 by 2 which is 31.2
the you divide 31.2 by what ever the base is and that is your height
Answer:
The population in 40 years will be 1220.
Step-by-step explanation:
The population of a town grows at a rate proportional to the population present at time t.
This means that:

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.
The initial population of 500 increases by 25% in 10 years.
This means that 
We apply this to the equation and find t.




Applying ln to both sides




So

What will be the population in 40 years
This is P(40).


The population in 40 years will be 1220.
INCREASE IN %: [(40280-1591)/1591]X 100% = 2,432&
For your info the increase between 2 amounts A₁ & A₂ =(A₁-A₂)/A₁