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Marizza181 [45]
2 years ago
5

Please help me i'm so bad at math

Mathematics
2 answers:
liubo4ka [24]2 years ago
7 0
Figure 1 is the answer, because all the sides are equal and parallel to each other which would make a cube
irina [24]2 years ago
3 0

Answer:

figure 1

Step-by-step explanation:

Think as of you have to assemble a cube

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Tim has 3 blue shirts and 2 red shirts in a drawer. He randomly picks one shirt, puts it back, and then picks another shirt. Wha
suter [353]

Answer:

D-6/25

Step-by-step explanation:

3 0
3 years ago
Can someone answer this please!!! I only have 5 mins and u will get Brainly too :)
luda_lava [24]
Better quality would help, have a good day/night
4 0
3 years ago
Harvey walks 45 feet in 8.5 seconds. What is Harvey's rate in feet per<br> second?
lilavasa [31]

The answer is : 5.29411764706

The answer when rounded:  5.29 or 5.3

I found the answer by simply dividing 45/8.5 - Remember that per means division!

6 0
2 years ago
A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 21.5, \sigma = 4.7

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.175*4.7

X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.04*4.7

X = 26.388

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0
3 years ago
James and Terry open a savings account that has a 2.75% annual interest rate, compounded monthly. They deposit $500 into the acc
katovenus [111]

Answer:

<h2>Option A is the answer(here the answer is calculated taking the whole value, without approximating it to a nearest value)</h2>

Step-by-step explanation:

Annual interest rate is 2.75%. Hence, the monthly interest rate is \frac{2.75}{12}

The amount will be compounded (20\times12) = 240 times.

Every month they deposits $500.

In the first month that deposited $500 will be compounded 240 times.

It will be 500\times [1 + \frac{2.75}{1200} ]^{240}

In the second month $500 will be deposited again, this time it will be compounded 239 times.

It will give 500\times [1 + \frac{2.75}{1200} ]^{239}

Hence, the total after 20 years will be 500\times [1 + \frac{2.75}{1200} ]^{240} + 500\times [1 + \frac{2.75}{1200} ]^{239} + ........+ 500\times [1 + \frac{2.75}{1200} ]^{1} = 160110.6741

7 0
3 years ago
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