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3 years ago

15

In a newspaper, it was reported that yearly robberies in Springfield were down 30% to 91 in 2013 from 2012. How many robberies w

ere there in Springfield in 2012?

1 answer:

Artyom0805 [142]3 years ago

3 0

Answer:

130

Step-by-step explanation:

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Divide 48 in the ratio of 2 : 4

dimaraw [331]

The correct answer is 8

7 0

3 years ago

Given f of x is equal to the quantity 8x plus 1 end quantity divided by the quantity 2x minus 9 end quantity, what is the end be

MaRussiya [10]

Using limits, it is found that the end behavior of the function is given as follows:

As x → -∞, f(x) → 4; as x → ∞, f(x) → 4.

<h3>How to find the end behavior of a function f(x)?</h3>

The end behavior of a function f(x) is given by the limit of f(x) as x goes to infinity.

In this problem, the function is:

$f(x) = \frac{8x - 1}{2x - 9}$

Considering that x goes to infinity, for the limits, we consider only the terms with the highest exponents in the numerator and denominator, hence:

$\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} \frac{8x}{2x} = \lim_{x \rightarrow -\infty} 4 = 4$ .

$\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{8x}{2x} = \lim_{x \rightarrow \infty} 4 = 4$ .

Hence the correct statement is:

As x → -∞, f(x) → 4; as x → ∞, f(x) → 4.

More can be learned about limits and end behavior at brainly.com/question/27950332

#SPJ1

7 0

2 years ago

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

noname [10]

Answer:

1. x = - 1 -y over 2

2. x = -4(2+y) over 3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The Statistics Club at Woodvale College sold college Y-shirts as a fundraiser. The result of the sale are shown below. Choose on

zavuch27 [327]

We are asked to find the probability that the student sold 11-15 T-shirts or less than 6 T-shirts.

The total number of club members = 2 + 14 + 12 + 3 + 6 + 1 = 38

Probability of 11-15 T-shirts:

From the table, 3 club members bought 11 - 15 T-shirts.

So the probability is 3/38

Probability of less than 6 T-shirts:

Less than 6 T-shirts means 1 - 5 plus 0 T-shirts.

Form the table, 14 club members bought 1 - 5 T-shirts and 2 club members bought 0 T-shirts.

Total club member who bought 1 - 5 and 0 T-shirts = 14 + 2 = 16

So the probability is 16/38

Now we have to add them together to find the probability that the student sold 11-15 T-shirts or less than 6 T-shirts.

(or means to add)

So the probability is 3/38 + 16/38 = 19/38 = 0.5000

Therefore, the correct answer is option c.

6 0

1 year ago

What is Permutations and Combinations?

marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

$\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }$

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

$\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}$

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

$\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }$

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

$\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}$

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0

2 years ago