Question

Camden is creating a model of a pyramid. The model created will need to be scaled up from the blueprint.

Answer 1

Answer:

A) DC equals EC times AC all over BC.

Step-by-step explanation:

We know that:

$DE\parallel AB$

Then by corresponding angles:

$\angle CAB\cong \angle CDE\text{ and } \angle CBA\cong \angle CED$

So, by AA-Similarity:

$\Delta CDE\sim \Delta CAB$

Corresponding sides of similar triangles are in proportion. Hence:

$\displaystyle \frac{DC}{AC}=\frac{EC}{BC}$

By multiplying both sides by AC:

$\displaystyle DC=\frac{EC\cdot AC}{BC}$

DC is equal to EC times AC over BC.

Hence, our answer is A.

Answer 2

DC = BC EC AC Figure: By similar triangle, It follows . that AC DC = BC EC Solve for DC AC DC = BC EC