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elena55 [62]
2 years ago
15

Use the calculator to graph the function y = 2x2 25x + 3. What are the coordinates of the turning point of the graph to the near

est hundredth?
Vertex = (
,
)
Mathematics
1 answer:
professor190 [17]2 years ago
5 0

The coordinates of the turning point of the graph of the quadratic equation is given by: (-6.25, -75.13).

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{b^2 - 4ac}{4a}

In this problem, the function is given by:

y = 2x² + 25x + 3.

Hence the coefficients are a = 2, b = 25, c = 3, then the coordinates of the vertex are given as follows:

  • x_v = -\frac{25}{2(2)} = -6.25
  • y_v = -\frac{25^2 - 4(2)(3)}{4(2)} = -75.13

The coordinates of the turning point of the graph of the quadratic equation is given by: (-6.25, -75.13).

More can be learned about the quadratic functions at brainly.com/question/24737967

#SPJ1

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meriva

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5/12

Step-by-step explanation:

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6 0
3 years ago
Solve for y.<br> 2x-3y=9
cluponka [151]

Answer:

y = 2/3x - 3

Step-by-step explanation:

Step 1: Write equation

2x - 3y = 9

Step 2: Solve for <em>y</em>

  1. Subtract 2x on both sides: -3y = 9 - 2x
  2. Divide both sides by -3: y = -3 + 2/3x
  3. Rewrite: y = 2/3x - 3
6 0
3 years ago
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
What’s the error<br> 3+1(6/2)<br> 4(6/2)<br> 4(3)<br> 12
Mumz [18]
I think the error is that you did not divide 6 by 2 first because you are supposed to so you would get 3, then you do 1 times 3 which is 3, then you have 3 plus 3 left which would be 6. i’m hoping this is right and that it helps you
4 0
3 years ago
Read 2 more answers
Can someone help me understand this!!!
otez555 [7]

Answer:

7b, 8a

Step-by-step explanation:

using the equation y=m(x)+b, m(x) is the slope, and b is the y intercept. Oky so for 7, its a slope of negative 2, and it has a y-intercept of 5, and if you look at graph b a  slope of -2 and would be a y-intercept of 5.

looking at equation a, its a Quadric function, f(x)=x^2, but it doesn't match the graph... strange because the graph for that equation would look like the image included. Hopefully this helps!

4 0
3 years ago
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