All categories

2 years ago

Write the following expression without negative exponents and without parentheses. (5x)^−3

Mathematics

2 answers:

Semmy [17]2 years ago

7 0

1
——-
5x^3

Bc neg exponent becomes positive if you divide one by it.

Dafna11 [192]2 years ago

5 0

Answer:

$\dfrac{1}{125x^3}$

Step-by-step explanation:

$(5x)^{-3} = \dfrac{1}{(5x)^3} = \dfrac{1}{5^3x^3} = \dfrac{1}{125x^3}$

You might be interested in

For which of the following inequalities is x≥4 a solution. x+3≥1 3x≥1 x-3≥1

pychu [463]

Answer:

x - 3 ≥ 1

Step-by-step explanation:

Solving each of the inequalities

x + 3 ≥ 1 ( subtract 3 from both sides )

x ≥ - 2

3x ≥ 1 ( divide each inequality by 3 )

x ≥ $\frac{1}{3}$

x - 3 ≥ 1 ( add 3 to both sides )

x ≥ 4 ← required solution

5 0

2 years ago

Read 2 more answers

the sum of three number is 202, the second is three more than the first number, the third number is three times the second numbe

sertanlavr [38]

Answer:

x = 38

y = 41

z = 123

Step-by-step explanation:

x + y + z = =202

y = x + 3

z = 3y = 3(x + 3) = 3x + 9

x + y + z = x + x + 3 + 3x + 9 = 5x + 12 = 202

5x + 12 = 202

5x = 190

x = 38

y = x + 3 = 41

z = 3y = 123

4 0

2 years ago

1. The probability of telesales representative making a sale on a customer call is 0.15.

Mumz [18]

Answer:

$n = 33$

$n = 19$

Step-by-step explanation:

From the question we are told that

The probability of telesales representative making a sale on a customer call is $p = 0.15$

The mean is $\mu = 5$

Generally the distribution of sales call made by a telesales representative follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the mean is mathematically represented as

$\mu = n* p$

=> $5= n * 0.15$

=> $n = 33$

Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

$P( X \ge 1) = 1 - P( X < 1 ) > 0.95$

=> $P( X \ge 1) = 1 - P( X =0 ) > 0.95$

=> $P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95$

=> $1 - [1 * 1* (0.85)^{n}] > 0.95$

=> $[(0.85)^{n}] > 0.05$

taking natural log of both sides

$n = \frac{ln(0.05)}{ln(0.85)}$

=> $n = 19$

3 0

2 years ago

(URGENT) need help with this so badly someone help asap

Fynjy0 [20]

The answer for A is 2,026. I set a porportion up which is 77/x = 3.8/100

The answer to B is 26

8 0

2 years ago

When driving at night, you should dim your headlights when:

Tatiana [17]

Answer:

Meeting or following another vehicle

Step-by-step explanation:

5 0

2 years ago