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Alla [95]
1 year ago
13

Quadratic equations Please Help Me!!!!!!

Mathematics
1 answer:
igor_vitrenko [27]1 year ago
7 0

The roots are 1 +√7 and 1 -√7.

<h3>What is Quadratic equation?</h3>

A quadratic equation in the variable x is an equation of the form ax² + bx + c= 0, where a, b, c are real numbers, a≠0

Given equation:

y= x²+2x-6

First,

Half the coefficient of x and add and subtract the square of (b/2)

y= x²+2x-6+(1)²-(1)²

y= x²+2x+(1)² -6 -(1)²

y= (x+1)² -7

Now, equate y=0

(x+1)² -7 =0

(x+1)² = 7

x+1= ±√7

x=1 ±√7

Hence, the roots are 1 +√7 and 1 -√7.

Learn more about quadratic equation here:

brainly.com/question/1962219

#SPJ1

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How do you reduce 75/100?
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Find the greatest common factor and then divide each number by it. 

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The Ferris wheel has a radius of 70 feet. The distance between the wheel and the ground is 4 feet. The rectangular coordinate sy
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x² + (y-74)² = 4900

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Circle equation: (x-h)² + (y-k)² = r²

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3 years ago
You have a part-time job. You work for 3 hours on Friday and 6 hours on Saturday. You also receive an allowance of $20 per week.
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Could someone pls explain this step by step? Really simplify it pls because I don't understand it at all.
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Answer:

  • y = 2x -6
  • y = -x +2
  • y = 4/5x -2
  • y = -3/2x +4

Step-by-step explanation:

The slope-intercept form of the equation for a line is ...

  y = mx +b . . . . . where m is the slope, and b is the y-intercept

For these equations, writing them in slope-intercept form means "solve for y." You always do any "solve for ..." problem by undoing the operations that are done to the variable. Addition is undone by adding the opposite. Multiplication is undone by division.

As always, whatever operation we perform on one side of the equal sign must also be performed on the other side. That is how the equal sign remains valid.

__

<h3>a)</h3>

  1/2y = x -3

All we need to do is get rid of the coefficient of y. We can do that by dividing by 1/2, or multiplying by 2. The latter is easier to see, perhaps.

 2(1/2y) = 2(x -3)

  y = 2x +2(-3)

  y = 2x -6

__

<h3>b)</h3>

  x +y = 2

Here, we need to undo the addition of x. We do that by adding (-x) to both sides of the equation.

  -x +x +y = -x +2

  y = -x +2

__

<h3>c)</h3>

  4x -5y -10 = 0

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Now, we need to divide by the coefficient of y. We do that to both sides of the equation.

  5y/5 = (4x -10)/5

  y = 4/5x -10/5

  y = 4/5x -2

__

<h3>d)</h3>

  3x = -2y +8

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