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3 years ago

Fin find the slope of the line passing through the points (-2, -7) and (9, -7)

Mathematics

1 answer:

Verdich [7]3 years ago

7 0

Answer:

The slope of the line passing through the given points (-2,-7) and (9,-7) is m=0

Step-by-step explanation:

Given that the line passing through the points (-2,-7) and (9,-7)

To find the slope of the line passing through the points :

$m=\frac{y_2-y_1}{x_2-x_1}$

Let $(x_1,y_1)$ and $(x_2,y_2)$ be the given points (-2,-7) and (9,-7) respectively

Substitute the points in the formula $m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-7-(-7)}{9-(-2)}$

$=\frac{-7+7}{9+2}$

$=\frac{0}{11}$

Therefore m=0

Therefore Slope m is 0

Therefore the slope of the line passing through the given points (-2,-7) and (9,-7) is m=0

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Simplify the following expression 6X2 plus 8X -3 minus 3X2-6

Murrr4er [49]

Answer:

-24

Step-by-step explanation:

I´m guessing by the big x sign you want me to multiply so the first step in the equation is to multiply because of PEMDAS so(6*2)+(8*-3)-3*2-6,

so 6*2=12,8*-3=-24,-3*2=-6

12+-24-6-6,

12-24=-12,-6+-6=-12

-12+-12=-24

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3 years ago

A square is inscribed in a circle with an area of 10 pi square inches. what is the area of the square

Naddik [55]

We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,

A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.

Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.

Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:

Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).

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3 years ago

Solve logarithmic equation: ln a=4 HELP

Olin [163]

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2 years ago

What’s the domain and range of this graph look at the arrow.

viva [34]

Answer:

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2 years ago

Day 4: As a landscaper, one of your clients wants a rectangular garden in which the length is five feet

liberstina [14]

Answer:

The Area of Rectangular Garden is 1044 feet²

Step-by-step explanation:

According to question

The perimeter of the garden = 82 ft

Let the length be L ft

The width be W ft

Now as per question

L = 5 + ( 2× W )

∵ Perimeter of Rectangle = 2 × ( Length + Width )

Or , Perimeter of Rectangle = 2 × ( L+ W )

Or, 82 = 2 × ( L+ W )

Or, 82 = 2 × [ 5 + ( 2 ×W ) + W ) ]

Or, 82 = 2 × ( 5 +3W )

Or, 41 = 5 + 3W

Or, 41 - 5 = 3W

So, 3W= 36

∴ W = $\frac{36}{3}$ = 12 feet

I.e Width = 12 feet

And L = 5 + ( 2× W )

Or, Length = 5 + 24 = 29 feet

Now The Area of Rectangle = Length × width

So, The Area of Rectangle = 29 ft × 36 ft

The Area of Rectangle is 1044 feet²

Hence The Area of Rectangular Garden is 1044 feet² Answer

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3 years ago