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marissa [1.9K]
1 year ago
6

Larry measures an object mass in grams which of the following object is he most likely measuring

Mathematics
1 answer:
Valentin [98]1 year ago
4 0

If Larry is measuring the object's mass, the object he is most likely measuring is; D: A horse.

<h3>How to Measure Mass?</h3>

There are different units of measurement for different parameters such as meters for length, seconds for time, Amperes for current e.t.c.

Now, we are talking about measurement of an object mass in grams. This means it has to be a living thing and as such from the options, the only living thing is a horse.

Read more about Mass Measurement at; brainly.com/question/5493941

#SPJ1

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Simplify 3 - (2-8).
lakkis [162]

Answer: 9

Step-by-step explanation:

2 - 8 = -6

3 - -6 = 9

6 0
3 years ago
Read 2 more answers
A student entering a doctoral program in educational psychology is required to select courses from the list of courses provided
SVEN [57.7K]

A) The possible three-course selections are as shown below.

B) The likelihood of selecting the combinations is 0.1 since there are 10 combinations in total.

<h3>How to solve probability combinations?</h3>

A combination operator can be used when we need to find the number of ways to select "k" items from a set of "n" items. It is also called a 'choose' operator where it is read as 'n choose k' and is represented and calculated as given below

From the choices given, there are 5 courses which are given below:

EPR 605

EPR 643

EPR 648

EPR 674

EPR 681

We need to find the combinations of 3 of these given 5 courses, which are given below (omitting the course code, EPR):

605-643-648

605-643-674

605-643-681

605-648-674

605-648-681

605-674-681

643-648-674

643-648-681

643-674-681

648-674-681

10 of the given choices of combinations are possible since they do not include a repeated course number.

The likelihood of selecting the combination of EPR 681, EPR 648, and EPR 605 is 0.1 since there are 10 combinations in total.

Complete question is;

A student entering a doctoral program in educational psychology is required to select three courses from the list of courses provided as part of his or her program. List all possible three-course selections. Comment on the likelihood that EPR 681, EPR 648, and EPR 605 will be selected. Select all the possible three-course selections below.

A. 648, 674, 605

B. 681, 648, 605

C. 681, 674, 605

D. 681, 681, 648

E. 674, 643, 674

F. 674, 605, 643

G. 681, 648, 674

H. 681, 681

I. 681, 648, 643

J. 648, 605, 643

K. 648, 674, 643

L. 681, 605, 643

M. 643, 694, 643

N. 681, 674, 643

Read more about Probability Combinations at; brainly.com/question/3901018

#SPJ1

8 0
2 years ago
For complex numbers z, let [tex] \[f(z) = \left\{
Nina [5.8K]

f(i)+f(1)+f(-1)+f(-i)=i^2+1+2+(-1)+2+(-i)^2=-1+3-1+2-1=2

6 0
2 years ago
In the inequality, what are all the possible values of x?
tangare [24]

Answer:

A

Step-by-step explanation:

-8*2+6≤2(-3*2+1)

= -10≤-10

5 0
2 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
2 years ago
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