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-Dominant- [34]
2 years ago
12

Help i don’t know how to find the answer

Mathematics
1 answer:
forsale [732]2 years ago
3 0

Answer:

what grade are you n?

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28) Find the circumference of a circle with a diameter of 2.5 inches. (it = 3.14)
antoniya [11.8K]

Answer: Circumference = 7.85 inches

Concept:

Here, we need to know the idea of circumference.

The circumference is the perimeter of a circle. The perimeter is the curve length around any closed figure.

Circumference = 2πr

r = radius

π = constant

Solve:

<u>Given information</u>

r = (1/2) d = (1/2) (2.5) = 1.25 inches

π = 3.14

<u>Given formula</u>

Circumference = 2πr

<u>Substitute values into the formula</u>

Circumference = 2 · (3.14) · (1.25)

<u>Simplify by multiplication</u>

Circumference = (2.5) · (2.14)

Circumference = \boxed {7.85 inches}

Hope this helps!! :)

Please let me know if you have any questions

3 0
3 years ago
Read 2 more answers
[this is urgent]Based on the triangle below, JK Is Included between angles:
Afina-wow [57]

Answer:

J and L

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How do I solve for x?
notka56 [123]
Solving:
\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
Make the Least Common Multiple (2,3,6)
2,3,6\:|2
1,3,3\:|3
1,1,1\:|\underline{2*3=6}


<span>Replace denominators and resolve:
</span>\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}
Cancel the dominators
\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}
3(3+4x) + 2(5-x) = 29
9 + 12x + 10 - 2x = 29
12x - 2x = 29 - 9 - 10
10x = 20 - 10
10x = 10
x =  \frac{10}{10}
\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark


7 0
3 years ago
Is 5+ 3 and 5-3 related facts explain
ololo11 [35]
Well maybe because the only thing that is different is the - and +
3 0
3 years ago
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
3 years ago
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