Y = -1x+b
replace x and y to find b
2 = -1*2+ b
b = 4
Final:
y = -1x + 4
Options
- (A)g(5) = 12
-
(B)g(1) = -2
- (C)g(2) = 4
- (D)g(3) = 18
Answer:
(D)g(3) = 18
Step-by-step explanation:
Given that the function, g, has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8
Then the following properties must hold
- The value(s) of x must be between -1 and 4
- The values of g(x) must be between 0 and 18.
- g(-1)=2
- g(2)=9
We consider the options and state why they are true or otherwise.
<u>Option A: g(5)=12</u>
The value of x=5. This contradicts property 1 stated above. Therefore, it is not true.
<u>Option B: g(1) = -2
</u>
The value of g(x)=-2. This contradicts property 2 stated above. Therefore, it is not true.
<u>Option C: g(2) = 4
</u>
The value of g(2)=4. However by property 4 stated above, g(2)=9. Therefore, it is not true.
<u>Option D: g(3) = 18</u>
This statement can be true as its domain is in between -1 and 4 and its range is in between 0 and 18.
Therefore, Option D could be true.
Answer:
A quadratic equation is second degree equation with the standard form ax^2+bx+c=0 as the highest power is 2.
__________________.
Answer:
Step-by-step explanation:
<u>Linear Combination Of Vectors
</u>
One vector 
is a linear combination of 
and 
if there are two scalars 
such as
In our case, all the vectors are given in 
but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.
We have
We set the equation
Multiplying both scalars by the vectors
Equating each coordinate, we get
Adding the first and the third equations:
Replacing in the first equation
We must test if those values make the second equation become an identity
The second equation complies with the values of 
and 
, so the solution is
