Answer: The required probability is 0.26.
Step-by-step explanation: Given that there are 60 red marbles and 40 blue marbles in a box 10 marbles are picked without replacement.
We are to find the probability of selecting 6 red marbles.
Since the marbles are picked up without replacement, so it is a situation of combination.
Let S denote the sample space of the experiment of drawing 10 marbles and E denote the event that 6 marbles are red.
So,
Therefore, the probability of event E is given by
Thus, the required probability is 0.26.
Answer:
$25
Step-by-step explanation:
i have an odd method of solving these types of equations
25x=100
x=4
340/4 = 85
85 x 3 = 255
Answer:
70 is the least common multiple of 10 and 7
Answer:
The data table is attached below.
Step-by-step explanation:
The average of a set of data is the value that is a representative of the entire data set.
The formula to compute averages is:
Compute the average for drop 1 as follows:
![\bar x_{1}=\frac{1}{3}\times[10+11+9]=10](https://tex.z-dn.net/?f=%5Cbar%20x_%7B1%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B10%2B11%2B9%5D%3D10)
Compute the average for drop 2 as follows:
![\bar x_{2}=\frac{1}{3}\times[29+31+30]=30](https://tex.z-dn.net/?f=%5Cbar%20x_%7B2%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B29%2B31%2B30%5D%3D30)
Compute the average for drop 3 as follows:
![\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33](https://tex.z-dn.net/?f=%5Cbar%20x_%7B3%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B59%2B58%2B61%5D%3D59.33)
Compute the average for drop 4 as follows:
![\bar x_{4}=\frac{1}{3}\times[102+100+98]=100](https://tex.z-dn.net/?f=%5Cbar%20x_%7B4%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B102%2B100%2B98%5D%3D100)
Compute the average for drop 5 as follows:
![\bar x_{5}=\frac{1}{3}\times[122+125+127]=124.67](https://tex.z-dn.net/?f=%5Cbar%20x_%7B5%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B122%2B125%2B127%5D%3D124.67)
The data table is attached below.
2: c
Step-by-step explanation:
3: a
by Supplementing each answer Into the equation
