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2 years ago

What is the answer to -2 2 3+ 1 5 6× 2

Mathematics

2 answers:

iVinArrow [24]2 years ago

8 0

Answer:

yr ans is 89.

hope it helps.

vodomira [7]2 years ago

5 0

Answer:

89 is the answer.

Step-by-step explanation:

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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

2 years ago

A famous mathematician and physicist named Archimede was born in 287 B.C. Write an integer to express the year of his birth.

il63 [147K]

-287 A.D (idk though)

8 0

2 years ago

Read 2 more answers

Five divided sixty eight

Schach [20]

5/68, or about 0.07

8 0

2 years ago

As a fundraiser, the Music Boosters wrapped gifts at the mall one weekend. Out of the 100 gifts they wrapped, 3/10 were for wedd

dangina [55]

Answer: The fraction of the gifts were for birthdays = $\dfrac{33}{100}$ .

Step-by-step explanation:

Given: fraction of gifts for weddings = $\dfrac{3}{10}$

fraction of gifts for baby showers = $\dfrac{37}{100}$

Rest of the gifts = $1-\dfrac3{10}-\dfrac{37}{100}$

$=\dfrac{100-30-37}{100}\ \ \ [\text{Making like fractions}]\\\\=\dfrac{100-67}{100}\\\\=\dfrac{33}{100}$

Hence, the fraction of the gifts were for birthdays = $\dfrac{33}{100}$ .

4 0

2 years ago

Question 1

Ilia_Sergeevich [38]

We will see that the perimeter of the rectangle is exactly 390 ft, so the statement is true.

<h3>Is the fence enough?</h3>

For a rectangle of length L and width W, the perimeter is given by:

P = 2*(L + W).

In this case, we know that:

L = 120 ft

W = 75 ft

Replacing that on the perimeter equation we get:

P = 2*(120 ft + 75 ft) = 390 ft

So the perimeter is exactly 390 ft, meaning that to put a fence around the parking lot the company will need at least 390 ft of fence.

So the statement is correct.

If you want to learn more about perimeters, you can read:

brainly.com/question/24571594

4 0

2 years ago