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Paul [167]
1 year ago
6

________ is a record in a relational database.

Computers and Technology
1 answer:
leonid [27]1 year ago
4 0

The answer that is a record in a relational database is called; A row

<h3>What is a record in relational database?</h3>

In relational databases, a record is defined as a group of related data held within the same structure. Furthermore, we can say that a record is a grouping of fields within a table that reference one particular object.

Now, in relational database, a row is called a record because each row, contains a unique instance of data or key for the categories defined by the columns.

Read more about Relational Database at; brainly.com/question/13262352

#SPJ12

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Ginny just enrolled in a C-SNP that uses the post-enrollment verification method. When will the plan send her a termination noti
Zolol [24]

The plan will be sent to her for a termination notification letter at the end of her first month of her enrollment.

<h3>What is a notification of termination?</h3>

A notice of termination is known to be that which is often given to an employee or a person and it states that it is the end of their employment or other contract.

Hence, The plan will be sent to her for a termination notification letter at the end of her first month of  her enrollment.

Learn more about verification method from

brainly.com/question/17274244

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6 0
2 years ago
Three different numbers need to be placed in order from least to greatest. For example, if the numbers are ordered 9, 16, 4, the
Savatey [412]

Answer:

what are the three different numbers?

8 0
3 years ago
Define a function typeHistogram that takes an iterator ""it"" (representing a sequence of values of different types) and builds
Alexeev081 [22]

Answer:

def typeHistogram(it,n):

   d = dict()

   for i in it:

       n -=1

       if n>=0:

           if str(type(i).__name__) not in d.keys():

               d.setdefault(type(i).__name__,1)

           else:

               d[str(type(i).__name__)] += 1

       else:

           break

   return list(d.items())

it = iter([1,2,'a','b','c',4,5])

print(typeHistogram(it,7))

Explanation:

  • Create a typeHistogram function that has 2 parameters namely "it" and "n" where "it" is an iterator used to represent a sequence of values of different types while "n" is the total number of elements in the sequence.
  • Initialize an empty dictionary and loop through the iterator "it".
  • Check if n is greater than 0 and current string is not present in the dictionary, then set default type as 1 otherwise increment by 1.
  • At the end return the list of items.
  • Finally initialize the iterator and display the histogram by calling the typeHistogram.
3 0
3 years ago
Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
A computer understand..............codes.<br>​
KiRa [710]

Answer:Computers only understand machine code - they do not understand high-level language code. Any high-level programming language code has to be converted to executable code. Executable code is also known as machine code which is a combination of binary code 0s and 1s.

Explanation:

6 0
2 years ago
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