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1 year ago

What are the minimum number of bits an address bus must have in a byte addressable memory system containing only 4 KiB of memory

Computers and Technology

1 answer:

posledela1 year ago

4 0

The minimum number of bits the address bus must have in the byte addressable memory system is 12

<h3>How to determine the minimum number of bits?</h3>

The memory size is given as;

Size = 4 KiB

Convert to bytes

Size = 4 * 2^10 bytes

Express 4 as 2^2

Size = 2^2 * 2^10 bytes

Multiply

Size = 2^12 bytes

The minimum number of bits is then calculated as;

2^n = Size

This gives

2^n = 2^12

Cancel out the base (2)

n = 12

Hence, the minimum number of bits is 12

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3 years ago

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2 years ago

Which of the following would be a valid method call for the following method? public static void showProduct (int num1, double n

Alenkinab [10]

Answer:

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for example: showProduct(10,10.5) is the correct answer even showProduct(10,10.0) is also correct but showProduct(10.0,10.5) or showProduct(10,10) or showProduct(10.0,10) are wrong calls.

Explanation:

The code is

public static void showProduct (int num1, double num2){
int product;
product = num1*(int)num2;
System.out.println("The product is "+product);
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showProduct is function which asks for two arguments whenever it is called, first one is integer and second one is of type double which is nothing but decimal point numbers. Generally, in programming languages, 10 is treated as integer but 10.0 is treated as decimal point number, but in real life they are same.

If showProduct( 10,10.0) is called the output will be 'The product is 100'.

Strange fact is that, if you enter showProduct(10,10.5) the output will remain same as 'The product is 100'. This happens because in the 3rd line of code,which is product=num1*(int)num2, (int) is placed before num2 which makes num2 as of type integer, which means whatever the value of num2 two is given, numbers after decimal is erased and only the integer part is used there.

This is necessary in JAVA and many other programming languages as you cannot multiply two different datatypes (here one is int and another is double). Either both of them should be of type int or both should be of type double.

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2 years ago