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2 years ago

The measure of A∠ is greater than twice the measure of B∠ . If the angles’ sum is 42 degrees, find the measure of A∠ .

Mathematics

1 answer:

Zarrin [17]2 years ago

3 0

Step-by-step explanation:

I think angle A = 21 degree

because in the question there is angle A Is twice means angle a + angle a= 4G degree

2 angle a=42 degree

42 divides by 2

answer is 21 degree

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Enter the indicated element.

Ymorist [56]

$a_{1,3} = 9$

Step-by-step explanation:

The elements of matrices are represented in the form

$a_{r,c}$

Here r is the row number and c is the column number.

Given matrix is:

$A = \left[\begin{array}{ccc}3&6&9\\2&4&8\end{array}\right]$

The elements of matrix will be represented by a_{r,c}

We have to find $a_{1,3}$

Which means that the first row and third column.

The first row is: 3 6 9 and the element in third column is: 9

So,

$a_{1,3} = 9$

Keywords: Matrices, Elements

Learn more about matrices at:

#LearnwithBrainly

6 0

3 years ago

What is the area of the square? Help me pls

Allushta [10]

Answer and Step-by-step explanation:

First, we need to find out the circumference of the circle.

We know that the circle has a radius of 1, and that we are finding the circumference. We'll use the circumference equation of a circle.

2 $\pi$ r

Plug in 1 for r.

$2\pi (1)$ = $2\pi$ = circumference of circle

Now, multiply the answer (the circumference) by 4 to get the perimeter of the square.

$2\pi$ x 4 = $8\pi$ = perimeter of square

Now, divide the perimeter by 4 to get what the side of the square is.

$8\pi$ ÷ 4 = $2\pi$

Now, multiply $2\pi$ by $2\pi$ (side times side) to get the area.

$2\pi$ x $2\pi$ = $4\pi$

The answer is A. $4\pi$

#teamtrees #PAW (Plant And Water)

I hope this helps!

Brainliest is appreciated,

8 0

2 years ago

Fundamental theorem of calculus <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D

mr_godi [17]

Answer:

$\displaystyle g'(s) = (s-s^4)^6$

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
$\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt \right] = f(x)$

Where a is some constant.

We can let:
$\displaystyle g(t) = (t-t^4)^6$

By substitution:

$\displaystyle g(s) = \int_6^s g(t)\, dt$

Taking the derivative of both sides results in:
$\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]$

Hence, by the Fundamental Theorem:

$\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\ & = (s-s^4)^6\end{aligned}$

3 0

2 years ago

Please answer the following question. Also please answer if you actually know it.

Iteru [2.4K]

Given : f(x)= 3|x-2| -5

f(x) is translated 3 units down and 4 units to the left

If any function is translated down then we subtract the units at the end

If any function is translated left then we add the units with x inside the absolute sign

f(x)= 3|x-2| -5

f(x) is translated 3 units down

subtract 3 at the end, so f(x) becomes

f(x)= 3|x-2| -5 -3

f(x) is translated 4 units to the left

Add 4 with x inside the absolute sign, f(x) becomes

f(x)= 3|x-2 + 4| -5 -3

We simplify it and replace f(x) by g(x)

g(x) = 3|x + 2| - 8

a= 3, h = -2 , k = -8

5 0

3 years ago

Which is greater? 2.17 or 2.2

goldfiish [28.3K]

Answer:

2.2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers