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lilavasa [31]
3 years ago
15

5 Jean owns a craft store. The protective safeguards endorsement of her BOP requires the store to have a functional automatic sp

rinkler system. A winter storm freezes the pipes to the sprinkler system, causing the system to shut down. How many hours does Jean have to restore the system before she must notify her insurer?
Mathematics
1 answer:
Contact [7]3 years ago
7 0

Answer:

48 hours

Step-by-step explanation:

If the automatic sprinkler system is shut down due to breakage, leakage, freezing, or opening of the sprinkler heads, the insured has 48 hours to restore the system before he or she must notify the insurer

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Find the equation of the exponential function represented by the table below
Gennadij [26K]

Answer:

y = 3^(1 + x)

Step-by-step explanation:

Notice that each time x increases by 1, y increases by a factor of 3.

Thus, the required equation  has the form y = 3^x.

Check:  If x = 0, do we get 3?  No.  Therefore we must modify the exponent:

y = 3^(1 + x)

Check:  If x = 0, do we get 3?  3^(1 + 0) = 3 (correct)

If x = 2, do we get 27?  3(1 + 2) = 3^3 + 27 (correct)

4 0
3 years ago
Power Series Differential equation
KatRina [158]
The next step is to solve the recurrence, but let's back up a bit. You should have found that the ODE in terms of the power series expansion for y

\displaystyle\sum_{n\ge2}\bigg((n-3)(n-2)a_n+(n+3)(n+2)a_{n+3}\bigg)x^{n+1}+2a_2+(6a_0-6a_3)x+(6a_1-12a_4)x^2=0

which indeed gives the recurrence you found,

a_{n+3}=-\dfrac{n-3}{n+3}a_n

but in order to get anywhere with this, you need at least three initial conditions. The constant term tells you that a_2=0, and substituting this into the recurrence, you find that a_2=a_5=a_8=\cdots=a_{3k-1}=0 for all k\ge1.

Next, the linear term tells you that 6a_0+6a_3=0, or a_3=a_0.

Now, if a_0 is the first term in the sequence, then by the recurrence you have

a_3=a_0
a_6=-\dfrac{3-3}{3+3}a_3=0
a_9=-\dfrac{6-3}{6+3}a_6=0

and so on, such that a_{3k}=0 for all k\ge2.

Finally, the quadratic term gives 6a_1-12a_4=0, or a_4=\dfrac12a_1. Then by the recurrence,

a_4=\dfrac12a_1
a_7=-\dfrac{4-3}{4+3}a_4=\dfrac{(-1)^1}2\dfrac17a_1
a_{10}=-\dfrac{7-3}{7+3}a_7=\dfrac{(-1)^2}2\dfrac4{10\times7}a_1
a_{13}=-\dfrac{10-3}{10+3}a_{10}=\dfrac{(-1)^3}2\dfrac{7\times4}{13\times10\times7}a_1

and so on, such that

a_{3k-2}=\dfrac{a_1}2\displaystyle\prod_{i=1}^{k-2}(-1)^{2i-1}\frac{3i-2}{3i+4}

for all k\ge2.

Now, the solution was proposed to be

y=\displaystyle\sum_{n\ge0}a_nx^n

so the general solution would be

y=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4+a_5x^5+a_6x^6+\cdots
y=a_0(1+x^3)+a_1\left(x+\dfrac12x^4-\dfrac1{14}x^7+\cdots\right)
y=a_0(1+x^3)+a_1\displaystyle\left(x+\sum_{n=2}^\infty\left(\prod_{i=1}^{n-2}(-1)^{2i-1}\frac{3i-2}{3i+4}\right)x^{3n-2}\right)
4 0
3 years ago
What facts about angles can you use to find the unknown angle measures?
ElenaW [278]
The sum of all three angles will always be 180 degrees.

6 0
3 years ago
Jon caught four fish that weighed a total of 252 pounds. The kingfish weighed twice as much as the amberjack and the white marli
Allushta [10]

Answer:

  • amberjack, 21 lbs
  • kingfish, 42 lbs
  • white marlin, 84 lbs
  • tarpon, 105 lbs

Step-by-step explanation:

Let k, a, m, t represent the weights of the kingfish, amberjack, marlin, and tarpon, respectively. The problem statement tells us ...

  • k = 2a
  • m = 2k
  • t = 5a
  • k + a + m + t = 252

Using substitution, we can rewrite the last equation as ...

... (2a) + (a) + 2(2a) + (5a) = 252

... 12a = 252 . . . . . collect terms

... a = 21 . . . . . . . . .divide by 12

Then k = 2a = 42; m = 2k = 84; t = 5a = 105.

8 0
3 years ago
I SEE YALL LOOKING BUT NOT HELPING PLEASE SOMEONE
bezimeni [28]

Answer:

the pitcure isnt clear.

8 0
3 years ago
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