The straight line distance from the starting point is 41 miles.
<u>Explanation:</u>
Given:
Distance covered towards north, n = 9 miles
Distance covered towards east, e = 40 miles
Distance from the origin to the end, x = ?
If we imagine this, then the route forms a right angle triangle
where,
n is the height
e is the base
x is the hypotenuse
Using pythagoras theorm:
(x)² = (n)² + (e)²
(x)² = (9)² + (40)²
(x)² = 1681
x = 41 miles
Therefore, the straight line distance from the starting point is 41 miles.
If AC=BD, than Quad ABCD is a rectangle
AC
√(3+3)²+(6-1)²
√6²+5²
√36+25
√61
BD
√(1+1)²+(2-7)²
√2²+(-5)²
√4+25
√29
Quad ABCD is not a rectangle because √61 and √29 are not equal.
Given t = time and h = height
From the equation.
h is the axis od symmetry
(h, k) is the vertex.
In the equation, h is 1 and k is 16.
So the maximum value is 16 at t = 1.
The ball reaches maximum at 16 and it takes t = 1 to reach the maximum point.
Answer:
x=11
Step-by-step explanation:
Since the lines in the middle are parallel, we know that both sides are proportional to each other.
6:48 can be simplified to 1:8
Since we know the left side ratio is 1:8, we need to match the right side with the same ratio
We can multiply the ratio by 5 to match 5:3x+7
5:40
5:3x+7
Now we can set up the equation: 40=3x+7
Subtract 7 from both sides
3x=33
x=11
