Line m passes through points (-3,5) and (1,-2) what is the slope of line m?

PLEASEEEEE HELLPPPP ME I NEED HELP ASAPPP I CANNOT FAIL THIS!!!!!!!

Elodia [21]

Answer:

1. Both Dan and Tess are correct.

Tess:

0.15 * 24.50 = 3.675

24.5 - 3.675 = 20.825

0.1 * 20.825 = 2.0825

20.825 + 2.0825 = 22.9075

Dan:

0.85 * 24.50 = 20.825

20.825 * 1.1 = 22.9075

Both Dan and Tess used methods that provided the correct answer. Both methods follow the same path, but Dan's method simply took less steps since he used percentages that would take out the correct number, unlike Tess' percentages which would give you the number that you would then need to take out.

2. First, convert Amy's and Mike's numbers to a decimal of the whole so it is easier to compare the numbers.

13% = 0.13 of the whole

Dan has 0.14 of the whole

0.5/6 = 0.083.. of the whole

Dan used the greatest amount of milk, using 0.14 of the 6 gallon container.

3.

2p + 12 = 58 | Create an equation to show the prices relations

2p = 46 | Take out the price of the concert ticket to leave us with the passes.

p = 23 | Divide by 2 to find the cost of each pass.

4.

x ≤ (18 - 6.5 - 5.75)/1.15

18 - 6.50 = 11.5 | Take out the price of the notebook from the total.

11.5 - 5.75 = 5.75 | Take out the amount of money that she wishes to save.

5.75 / 1.15 = 5 | Divide by the price of each candy to find the max amount that she can buy.

Andrea has enough money to buy up to 5 candy bars.

x ≤ 5

8 0

3 years ago

Read 2 more answers

8x – 12y = 48<br> Find the x-intercept and y-intercept

Sindrei [870]

Answer:

my answer came out to x = 6 + 1.5y

Step-by-step explanation:

3 0

3 years ago

PLZ HELL FAST WILL GIVE BRAINLIEST

Sauron [17]

${3x}^{2} - 5x = - 8 \\ {3x}^{2} - 5x + 8 = 0$

This equation has the next form:

${ax}^{2} + bx + c = 0$

To find if the equation has two complex solutions we have to check if the discriminant is negative, as follows:

${b}^{2} - 4ac \\ ( { - 5})^{2} - 4 \: . \: 3 \: . \: 8 = 25 - 96 = - 71 < 0$

Then, the first case has two complex solutions.

In the second case,

${2x}^{2} = 6x - 5 \\ {2x}^{2} - 6x + 5 = 0$

The discriminant in this case is:

$( { - 6})^{2} - 4 \: . \: 2 \: . \: 5 = 36 - 40 = - 4 < 0$

Then, the second case has two complex solutions.

In the third case,

$12x = {9x}^{2} + 4 \\ { - 9x}^{2} + 12x - 4 = 0$

The discriminant in this case is:

${12}^{2} - 4 \: . \: ( - 9) \: . \: ( - 4) = 144 - 144 = 0$

Then, the third case has two real solutions.

In the fourth case,

${ - x}^{2} - 10x = 34 \\ { - x}^{2} - 10x - 34 = 0$

The discriminant in this case is:

$( { - 10})^{2} - 4 \: . \: ( - 1) \: . \: ( - 34) = 100 - 136 = - 36 < 0$

Then, the fourth case has two complex solutions.

7 0

2 years ago

Read 2 more answers

How do you simplify <img src="https://tex.z-dn.net/?f=7%5Csqrt%5B4%5D%7B80pq%5E%7B2%7Dr%5E%7B8%7D%20%20%7D" id="TexFormula1" tit

kondor19780726 [428]

Answer:

$14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}$

Step-by-step explanation:

The expression to simplify in this problem is

$7\sqrt[4]{80pq^2r^8}$

Which can be rewritten as

$7(80pq^2r^8)^{\frac{1}{4}}$

Or also as

$7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot (q^2)^{\frac{1}{4}} \cdot (r^8)^{\frac{1}{4}}$

Now we can apply the following rule for the calculation of the power of a power:

$(a^m)^n = a^{m\cdot n}$

So we get:

$7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

Which can therefore be rewritten as

$7\cdot (2^4\cdot 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

And so, we get

$7\cdot 2 \cdot ( 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

which can be finally rewritten as

$14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}$

6 0

3 years ago

What is 3- 22 tenths

expeople1 [14]

22/10= 0.2

3-0.2= 2.8

7 0

3 years ago