Answer:
C) They are perpendicular lines.
Step-by-step explanation:
We first need to find the slope of the graph of the lines passing through these points using:

The slope of the line that passes through (−12, 15) and (4, −5) is


The slope of the line going through (−8, −9) and (16, 21) is



The product of the two slopes is

Since

the two lines are perpendicular.
Assume that 100% = 45 sales and 35% = X sales amount
You can create a ratio to help you solve for x
45 = 100%
x = 35 %
Which is equal to this fraction: (45/x) = (100/35)
Solving for X by cross multiplying and dividing by 100:
[(45)(35)] / 100 = X = 15.75 = 16 sales (rounded up)
You would need at least 16 sales to increase sales total by 35%
Answer:
As shown in picture, this is a trapezoid.
The area of a trapezoid is calculated by:
A = (base1 + base2) x height x (1/2)
To work out A, we need to find out base1, base2, and height.
base1 = YZ = 
base2 = XW =
Otherwise, the height (distance between base1 and base2) is 4 as shown in picture.
=> A = (3 + 7) x 4 x (1/2) = 20
Hope this helps!
:)