Answer:
i will go with C TO BE REAL
Step-by-step explanation:
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
x = 5 and -2
Step-by-step explanation:
Given the function of x to be;
f(x) = (x-5)(x+2)/x+1
The value of x that will make the function zero can be calculated for by equating the given function to zero first to have;
If f(x) = 0, then;
(x-5)(x+2)/x+1 = 0
Cross multiplying;
(x-5)(x+2) = 0
(x-5) = 0 and x+2 = 0
x = 5 and x = -2
The value of x that will make the function zero is therefore 5 and -2
Sorry, I think there is missing context?
Answer: b=0
Step-by-step explanation:
0.5b+4=2(b+2)
0.5b+4=2b+4
4=1.5b+4
0=1.5b
b=0