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melisa1 [442]
2 years ago
10

Question 2 of 25

Biology
1 answer:
Kitty [74]2 years ago
6 0

Answer:

The structure labeled X in the diagram is a membrane protein.

Explanation:

Membrane proteins are integral parts of the cell membrane that enable the transfer of ions like sodium, potassium and chlorine and small molecules like glucose through the lipid bilayer. They differ from other types of cell proteins by their structure. As you can see on the diagram, hey form channels that enable specific ions or molecules to pass to the other side of the membrane.

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4 major types of animal tissue
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epithelial tissue, connective tissue, muscle tissue, and nervous tissue.

Explanation:

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What is cytokinesis
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Cytokinesis is the part of the cell division process during which the cytoplasm of a single eukaryotic cell divides into two daughter cells.
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Why is it important for scientists to be able to remove DNA from an organism? List 2 reasons.
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To make changes to it or to take out some genes of interest
5 0
3 years ago
In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

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3 years ago
How does the heart detect changes in body activity?
madreJ [45]
By circulation of blood
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