Answer:
15 apples
Step-by-step explanation:
Answer: -1
The negative value indicates a loss
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Explanation:
Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)
There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die
There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18
Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event.
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9
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In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9
The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9
Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7
Add up those results
3+3+(-7) = -1
The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.
Note: because the expected value is not 0, this is not a fair game.
Answer:31 or 30.5 orrr 61/2
Step-by-step explanation:
quick mathz
Answer:
- 8, 15, 17 — yes
- 15, 20, 25 — yes
- 20, 48, 52 — yes
- 2, 9, 11 — no
- 39, 80, 89 — yes
Step-by-step explanation:
The squares of the three numbers in each of the given triples are listed. When the sum of the first two numbers is equal to the third, the set of numbers in the triple is a Pythagorean triple.
{64, 225, 289}, yes
{225, 400, 625}, yes — a 3,4,5 triple multiplied by 5
{400, 2304, 2704}, yes — a 5,12,13 triple multiplied by 4
{4, 81, 121}, no*
{1521, 6400, 7921}, yes.
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* the smallest set of integers that is a Pythagorean triple is {3, 4, 5}. The number 2 in this group tells you this cannot be a PT.
