The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
Answer:
The answer is option D.
3u + 1 + 7y
All the terms here are different and cannot be combined
Hope this helps you
Answer:
6(8x-3)x(3x²-7)
Step-by-step explanation:
144x³-54x²-336x+126
=6(24x³-9x²-56x+21)
=6(3x²x(8x-3)-7(8x-3))
=6(8x-3)x(3x²-7)
Answer: c) There is not enough evidence to reject H0
Step-by-step explanation:
Answer:
y = -2x - 2
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Points: (3, 4)
Slope: -2
y = -2x + b
4 = -2 ( 3 ) + b
4 = -6 + b
b = -2
y = -2x - 2
