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Murrr4er [49]
3 years ago
12

Please help thank you

Mathematics
1 answer:
allochka39001 [22]3 years ago
4 0
I think it's 20. Sorry if it's wrong
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True or false the values [x] and [-x] are always equal
RoseWind [281]

Answer:

If you mean |x| and |-x| yes they are equal.

Step-by-step explanation:

Brackets do not exactly specify the meaning of absolute value.

On most keyboards, above the enter button on the main keyboard part (not the keypad one) there is a back slash symbol \ and if you hold shift, there might be another symbol | which more accurately represents absolute value,

If you aren't talking about the absolute value, then no.

4 0
3 years ago
5/2x-3 is this a monomial, binomial, or trinomial
Serga [27]
Its a binomial. There are two terms


6 0
3 years ago
The local zoo is filling two water tanks for the elephant exhibit. One water tank contains 30 gal of water and is filled at a co
kakasveta [241]
You first have to set up the two equations. Y is equal to the total number of gallons in a tank and x is equal to the number of hours the tanks are filling.

Since the two equations both equal y I can make them equal each other. I then solved for x as you see and got -4.

Once I found my x value I now needed to find my y. You only needed to chose one equation to solve for y, so I decided to do the first one. I plugged in -4 where my x value currently was and solved for y. I got 2.


If you have any questions please comment!! Hope this helps!!
3 0
3 years ago
Solve y=-3x² + 4.5x – 20<br> Use the Quadratic formula
statuscvo [17]

Answer:

x=0.75 \pm 2.47067i

Step-by-step explanation:

Quadratic Formula: x=\frac{-b \pm \sqrt{b^2-4ac} }{2a}

√-1 is imaginary number i

Step 1: Define

y = -3x² + 4.5x - 20

a = -3

b = 4.5

c = -20

Step 2: Substitute and Evaluate

x=\frac{-4.5 \pm \sqrt{4.5^2-4(-3)(-20)} }{2(-3)}

x=\frac{-4.5 \pm \sqrt{20.25-240} }{-6}

x=\frac{-4.5 \pm \sqrt{-219.75} }{-6}

x=\frac{-4.5 \pm \sqrt{219.75}(\sqrt{-1} ) }{-6}

x=\frac{-4.5 \pm i\sqrt{219.75} }{-6}

x=\frac{4.5 \pm i14.824 }{6}

x=0.75 \pm 2.47067i

7 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0
3 years ago
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