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3 years ago

Solve - 4z+3=6+ 2 z

Mathematics

2 answers:

malfutka [58]3 years ago

7 0

-4z plus 3 equal is to 6 plus 2z

Answer will be 3=-2z

iren [92.7K]3 years ago

3 0

-4z+3=6+2z
-4z-2z=6-3
-6z=3
— —
-6 -6
z= -1/2

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Paired t‐Test for Mean Comparison with Dependent Samples To study the effects of an advertising campaign at a supply chain, seve

Lapatulllka [165]

Answer:

a) $t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.7 -0}{\frac{0.678}{\sqrt{5}}}=2.308$

$p_v =P(t_{(4)}>2.308) =0.0411$

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

b) The p value is illustrated on the figure attached.

If we select $\alpha=0.01$ we see that $p_v >\alpha$ so then we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Part a

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

1=test value old , 2 = test value new

1: 5.2 6.5 7.2 5.7 7.6

2: 6.4 7.8 6.8 6.5 8.2

The system of hypothesis for this case are:

Null hypothesis: $\mu_2- \mu_1 \leq 0$

Alternative hypothesis: $\mu_2 -\mu_1 >0$

The first step is calculate the difference $d_i=y_i-x_i$ and we obtain this:

d: 1.2, 1.3, -0.4, 0.8, 0.6

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}=0.7$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =0.678$

The 4 step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.7 -0}{\frac{0.678}{\sqrt{5}}}=2.308$

The next step is calculate the degrees of freedom given by:

$df=n-1=5-1=4$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_{(4)}>2.308) =0.0411$

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

Part b

The p value is illustrated on the figure attached.

If we select $\alpha=0.01$ we see that $p_v >\alpha$ so then we have enough evidence to FAIL to reject the null hypothesis.

7 0

3 years ago

A number has two digits. The digit at tens place is four times the digit at units place. If 54 is subtracted from the number, th

iren2701 [21]

"The digit at tens place is four times the digit at units place."

How many possible numbers are there?

1 in the units place: 41

2 in the units place: 82

If you try 3 in the units place, 4 * 3 = 12, you'd get 123, and now it's a three-digit number, so the only possibilities are 41 and 82.

41 or 82

If you subtract 54 from 41, you get a negative number, so 41 cannot be the number.

82 - 54 = 28, which has the digits of 82 in reverse order.

Answer: 82

4 0

3 years ago

Complete the chart please :)

Viktor [21]

Answer:

x=9 output 1=20.25

Output 2 equals 27

Step-by-step explanation:

This function is constant, so you do input times 2.25 for each.

The box below 6 is 9 because we are counting by 3

9 x 2.25=20.25

12 x 2.25=27

Hope this helped :)

8 0

3 years ago

Read 2 more answers

Simplify x^2 -x-6/4x^3 * 2x^2 +2x/x^2+5x+6 And PLS show work.

Sedbober [7]

To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

$( \frac{x^{2}-x-6}{4x^{3}}) (\frac{x^{2}+2x}{x^{2}+5x+6} )$

2. First, you must factor the polynomials in the numerator and in the denominator and then simplify the expression:

$(\frac{(x-3)(x+2)}{4x^{3}} ) (\frac{2x(x+1)}{(x+3)(x+2)})=\frac{(x-3)(x+1)}{2x^{2}(x+3)(x+2)}$

The answer is: $\frac{(x-3)(x+1)}{2x^{2}(x+3)(x+2)}$

3 0

4 years ago

Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B

labwork [276]

Answer:

$x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

Step-by-step explanation:

we are given that $x^3-9x+2x^2-18$

w are sked to step by step factorise the above polynomial

$\left(x^3+2x^2\right)+\left(-9x-18\right)$

$-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)$

$-9x-9\cdot \:2$

$-9\left(x+2\right)$

$\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)$

$-9\left(x+2\right)+x^2\left(x+2\right)$

$\left(x+2\right)\left(x^2-9\right)$

$x^2-9:\quad \left(x+3\right)\left(x-3\right)$

$x^2-9$

$\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2$

$=x^2-3^2$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$x^2-3^2=\left(x+3\right)\left(x-3\right)$

Hence

$x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)$

a) The jay mistake was he did not factorise $x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

8 0

4 years ago

Read 2 more answers

Solve - 4z+3=6+ 2 z​

Solve - 4z+3=6+ 2 z