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Gre4nikov [31]
2 years ago
9

Complete the chart please :)

Mathematics
2 answers:
Viktor [21]2 years ago
8 0

Answer:

x=9   output 1=20.25

Output 2 equals 27

Step-by-step explanation:

This function is constant, so you do input times 2.25 for each.

The box below 6 is 9 because we are counting by 3

9 x 2.25=20.25

12 x 2.25=27

Hope this helped :)

aleksley [76]2 years ago
4 0

Answer:

Step-by-step explanation:

muffin times 2.25=output

so 12x2.25=27

and also x=9

so 9x2.25=20.25

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Nancy hopes to collect 100 oysters from the ocean. She has
Tanzania [10]

Answer:

<h2>15 oysters have been collected</h2>

Step-by-step explanation:

15/100 x 100

100 on the right hand side being the oysters she must collect and the 15% being the percentage of oysters she has collected divided by 100 which is used when finding out the percentage of numbers

4 0
2 years ago
What is the exact value of tan4pi/3?
MA_775_DIABLO [31]

Answer:

<h2><u>√ 3</u></h2>

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the value of |C| in this matrix
damaskus [11]

Answer:

-12

Step-by-step explanation:

required value is det(C)

detC = (-6×4)-(6×-2)

so |C| = -24+12

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6 0
3 years ago
Shannon walked 1 2/3 miles on Wednesday and 2 3/5 miles on Thursday. What was the total distance, in miles,Shannon walked during
Eduardwww [97]
First, add the integers to get 3. Then, add 2/3 and 3/5 by converting them into fifteenths, for a total of 19/15, or 1 4/15. Add these together to get 4 4/15 miles.
8 0
3 years ago
Dy/dx if y = Ln (2x3 + 3x).
NeTakaya

Answer:

\frac{6x^2+3}{2x^3+3x}

Step-by-step explanation:

You need to apply the chain rule here.

There are few other requirements:

You will need to know how to differentiate \ln(u).

You will need to know how to differentiate polynomials as well.

So here are some rules we will be applying:

Assume u=u(x) \text{ and } v=v(x)

\frac{d}{dx}\ln(u)=\frac{1}{u} \cdot \frac{du}{dx}

\text{ power rule } \frac{d}{dx}x^n=nx^{n-1}

\text{ constant multiply rule } \frac{d}{dx}c\cdot u=c \cdot \frac{du}{dx}

\text{ sum/difference rule } \frac{d}{dx}(u \pm v)=\frac{du}{dx} \pm \frac{dv}{dx}

Those appear to be really all we need.

Let's do it:

\frac{d}{dx}\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot \frac{d}{dx}(2x^3+3x)

\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (\frac{d}{dx}(2x^3)+\frac{d}{dx}(3x))

\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (2 \cdot \frac{dx^3}{dx}+3 \cdot \frac{dx}{dx})

\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (2 \cdot 3x^2+3(1))

\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (6x^2+3)

\frac{d}{dx}(\ln(2x^3+3x)=\frac{6x^2+3}{2x^3+3x}

I tried to be very clear of how I used the rules I mentioned but all you have to do for derivative of natural log is derivative of inside over the inside.

Your answer is \frac{dy}{dx}=\frac{(2x^3+3x)'}{2x^3+3x}=\frac{6x^2+3}{2x^3+3x}.

3 0
3 years ago
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