1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Margaret [11]
3 years ago
5

The tempature was very cold,tgen it doubled,then it dropped 10 degrees,and then it increased by 40 degrees.The tempature is now

16 degrees.What was the starting tempature?
Mathematics
2 answers:
ycow [4]3 years ago
4 0

Answer

The initial temperature was T = -7 degrees

Step-by-step explanation:

Let the initial temperature be T.

- The tempature was very cold

Temperarure = T

- Then it doubled

Temperature = 2T

- Then it dropped 10 degrees

Temperature = 2T - 10

- And then it increased by 40 degrees.

Temperature = 2T - 10 + 40 = 2T + 30

The tempature is now 16 degrees

Temperature = 16 degrees

2T + 30 = 16

2T = -14

T = -7 degrees

Hope this Helps!!!

UkoKoshka [18]3 years ago
4 0

Answer:

The starting temperature was -7 degrees

Step-by-step explanation:

Let's call the inicial temperature by 'X'.

First the temperature doubled, so now it is 2X.

Then, it dropped 10 degrees, so now it is 2X - 10

Then, it increased by 40 degrees, so now it is 2X - 10 + 40 = 2X + 30

Now, the temperature is 16 degrees, so we have that:

2X + 30 = 16

2X = 16 - 30

2X = -14

X = -7

The starting temperature was -7 degrees

You might be interested in
Write 100,000+4,000+40+7 in standard notation
labwork [276]
In standard notation it is 104,047
8 0
3 years ago
Read 2 more answers
Can you find the first and third one please!
fenix001 [56]

Answer:

The first ones area is 35 cm squared

The third ones area is 32 cm squared

Step-by-step explanation:

A=1/2H (B1+B2)

35=2.5(8+6)

32=2(7+9)

7 0
3 years ago
W^2-49=0 what are both solutions one is what's the other??
Alborosie
W² - 49 = 0
w² - 7² = - 
(w-7)(w+7)=0
w -7=0 , or w + 7 =0
w=-7, w=7

Answer: -7, 7.
3 0
3 years ago
A square has a perimeter of 12 cm. What is its area?
Zigmanuir [339]

a. 9 cm 2 because each side would be 3 and length x width would be 3 x 3 = 9

3 0
3 years ago
Read 2 more answers
The area of a rectangle is 12.65 m^2. the length measures 5.5 m. what is the width of the rectangle?
Nat2105 [25]

Answer:

The width of the rectangle is 2.3 m

Step-by-step explanation:

Now, when we are asked to find the area of the rectangle, we will use the formula: Area= length * width. We should be given with at least two values, and then we can use the above formula and can find the third variable.

Now, we are given that the area of a rectangle is 12.65 m^2 and the length measures 5.5 m

So the width is given as:

Area= length * width\\\Rightarrow 12.56= 5.5 * width\\\Rightarrow width= \frac{12.56}{5.5}\\\Rightarrow width=2.3 ~m

So this is the required with of the rectangle.

4 0
4 years ago
Read 2 more answers
Other questions:
  • Plz help need help fast plz
    15·1 answer
  • if there are 8 chocolate chip cookies out of 20 total cookies in a jar what is the probability that you will randomly choose a c
    10·2 answers
  • A soft drink can is h centimeters tall and has a radius of r cm. The cost of material in the can is 0.0005 cents per cm2 and the
    10·2 answers
  • (–1) 5 – (–6) – 5 = <br> a. –3 <br> b. –2 <br> c. 5 <br> d. 0
    12·2 answers
  • Number 10 <br> I think it's 1 but I'm not exactly sure
    15·1 answer
  • the diagonals PR and QS of a rhombus intersect each other at point O. prove that 2(PQ) + 2(QR) + 2(RS)+ 2(PS) = 4 (2(OP)+2(OQ))
    11·1 answer
  • Complete the following sentence:Trianlge ACB is similar to __ ____________
    10·1 answer
  • HELPPP PLEASE ANSWER FAST CLASS IS ALMOST OVER!!!
    14·1 answer
  • (**10 POINTS**)<br> Create two expressions, 1 in the form a (b+c) and a (b - c), that equal 100.
    7·1 answer
  • 4 - 2(x-4)/ 3= 3(2x+5)/2<br>linear equation in one variable<br>no spamms❌❌❌❌​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!