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2 years ago

This circle is centered at the origin, and the length of its radius iS 6. What is

Mathematics

1 answer:

VikaD [51]2 years ago

4 0

$\sf{\qquad\qquad\huge\underline{{\sf Answer}}}$

The equation of circle in standard form can be represented as :

$\qquad \sf \dashrightarrow \:(x - h) {}^{2} + (y - k) {}^{2} = r {}^{2}$

where,

h = x - coordinate of centre = 0

k = y - coordinate of centre = 0

r = radius of circle = 6 units

now, let's plug in the values :

$\qquad \sf \dashrightarrow \:(x - 0) {}^{2} + (y - 0) {}^{2} = 6 {}^{2}$

$\qquad \sf \dashrightarrow \: {x}^{2} + {y}^{2} = 36$

That's the required equation of circle.

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*look at the image* whoever answers will get brainliest

Vanyuwa [196]

It might be 8 hope this helped good luck on ur assignment

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3 years ago

ASAP NEED HELP ON MY MATH RETAKE I NEED HELP PLZZZ IM BEGGING YALL

Sindrei [870]

Answer:

B) There tends to be a linear association between variables

c) the data includes one or more outliers

8 0

3 years ago

The nth term of a sequence is n^2 + 20.

Olegator [25]

Answer:

$\large\boxed{a)\ 21,\ 24,\ 29}\\\boxed{b)\ \text{five terms}}$

Step-by-step explanation:

$a_n=n^2+20\\\\a)\\\\\text{Substitute}\ n=1,\ n=2\ \text{and}\ n=3\ \text{to the }\ a_n:\\\\a_1=1^2+20=1+20=21\\\\a_2=2^2+20=4+20=24\\\\a_3=3^2+20=9+20=29$

$b)\\\\\text{You have to solve the inequality:}\\\\n^2+20$

3 0

3 years ago

Given that z is a standard normal random variable, find z for each situation. The area between 0 and z is .4750. Answer The area

algol13

Answer:

$P(0$

And solving for z we have

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.975,0,1)"

And we got z =1.96

$P(Z>z)= 0.1314$

And we can use the complement rule and we got:

$P(Z>z) = 1-P(Z$

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.8686,0,1)"

And we got z =1.120

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.67,0,1)"

And we got z =0.440

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

We want this probability:

$P(0$

And solving for z we have

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.975,0,1)"

And we got z =1.96

For the next part we want to calculate:

$P(Z>z)= 0.1314$

And we can use the complement rule and we got:

$P(Z>z) = 1-P(Z$

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.8686,0,1)"

And we got z =1.120

For the next part we want to calculate:

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.67,0,1)"

And we got z =0.440

6 0

3 years ago

Help.. or die.. you decide.

Studentka2010 [4]

Answer:

Problem 1:

x = 12 unit ; y = 120 ; z = 60 ; perimeter = 58 unit

Problem 2:

FG = 16 unit ; EG = 2√153 unit ; y = 5 unit

Step-by-step explanation:

Problem 1

Since ABCD is a parallelogram. so,

∠ABC = ∠ADC [Since opposite angles of a parallelogram are equal]

but, ∠ADC = 120° [given]------------(1)

So, ∠ ABC = y° = 120° ----------------(2)

Again, sum of two consecutive angles of a parallelogram is, 180°, so,

∠BCD + ∠ADC = 180°

So, ∠BCD =z° = 180° - 120° = 60° [Putting the value of ∠ADC from (1)]-----(3)

Again, since opposite sides of a parallelogram are equal,

so, BC = AD

⇒ (x + 5) = 17

⇒ x = 12------------------------(4)

So, AB = 12 unit , AD = 17 unit

So, the perimeter of the parallelogram is given by,

2(AB + AD)

= $2 \times (12 + 17)$ unit

= 58 unit --------------------------------------------------------------(5)

Problem 2

Perimeter of parallelogram EFGH = 52 unit

So, 2(EH + GH) = 52 unit

⇒ 2 ( x + x + 6) = 52

⇒ 4x = 40

⇒ x = 10

Now, FG = EH [since opposite sides of a parallelogram are equal]

= (x + 6) unit

= (10 + 6) unit = 16 unit ------------------------------(1)

Again for a parallelogram, the diagonals bisect each other.

so, EG = $2 \times \sqrt{153}$

= 2√153 unit -----------------------------------------(2)

and,

3y - 10 = y

⇒ y = 5 -----------------------------------------------(3)

5 0

3 years ago