2 years ago

The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y.

Mathematics

2 answers:

Mademuasel [1]2 years ago

5 0

Answer:

Step-by-step explanation:

bulgar [2K]2 years ago

3 0

Answer: A

$y=\dfrac{3*10^8}{x}\\\\if\ x=3*10^9\ then\\y=\dfrac{3*10^8}{3*10^9}=\dfrac{1}{10}=1*10^{-1}\ (m)$

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4 years ago

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Step-by-step explanation:

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3 years ago

Simplify the expression 1/√(1-cos^2 x) . Remember cos x= 1/csc x

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First, we are going to use the Pythagorean identity: $sin^2(x)+cos^2(x)=1$ to rewrite our expression. Solving for $sin^2(x)$ in our Pythagorean identity we get that $sin^2(x)=1-cos^2(x)$ , so we can rewrite our expression as follows:
$\frac{1}{ \sqrt{1-cos^2(x)} } = \frac{1}{ \sqrt{sin^2(x)} } = \frac{1}{sin(x)}$

Next, we are going to use the trig identity: $csc(x)= \frac{1}{sin(x)}$ to completely simplify our expression:
$\frac{1}{sin(x)} =csc(x)$

We can conclude that $\frac{1}{ \sqrt{1-cos^2(x)} }=csc(x)$