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In-s [12.5K]
3 years ago
8

Let f(x)=6x^2-ax^3 what is the value of a if f has a point of inflection at X=6

Mathematics
1 answer:
Gnoma [55]3 years ago
6 0
This is really a easy question just plug what they give you in
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HELP ASAP: Find a hyperbola's equation with vertices at (-7, 0) + (7, 0) and co-vertices (0, -4) + (0, 4).
Harlamova29_29 [7]

Answer:

16x^2 - 49y^2 = 784

Step-by-step explanation:

as we know that this is the standard equation of hyperbola bcz 1 coordinate of vertices is 0.

since in vertices x coordinate is present and y coordinate is 0 so Tranverse axis of hyperbola is along x axis .

vertices in general = (a,0) and (-a,0)

vertices given = ( 7,0) and (-7 , 0)

so a=7

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now equation for x axis is:

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by putting values we observe the ans is

16x^2 - 49y^2 = 784

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3 years ago
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Solve for x: 1 < x + 3 < 4
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Answer:

The answer is D

Step-by-step explanation:

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6 1/2 divided by 3/4 pls someone help ASAP
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Answer:

Its basically asking 6.50 / .75 which is 8.6 or you can round it to 8.7

Step-by-step explanation:

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