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zimovet [89]
2 years ago
10

Match each rational expression to its simplest form.

Mathematics
1 answer:
prohojiy [21]2 years ago
4 0

Answer:the force of b is the force of a witch makes the answer b

Step-by-step explanation:

and its very easy to understand BC i just need the points

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Which statement about the radius of a sphere is true?
katrin [286]
<h2>Answer:</h2>

The statement that is true about the radius of a sphere is:

The radius is a line segment from the center point to the surface of the sphere.

<h2>Step-by-step explanation:</h2>

We know that the radius of a circle/sphere is a line segment that joins the center of circle/sphere to any point on the circumference/ surface of the circle/sphere.

Also, in a circle the radius is the length such that each point on the circumference are equidistant from the center of the circle.

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Find the domain of f(x)=square root x^2−36.
vichka [17]
f(x)= \sqrt{x^{2}-36}   \\  \\ D: x^{2}-36 \geq 0 \\  \\ (x-6)(x+6)  \geq 0 \\  \\ x+6=0 \ \vee \ x-6=0 \\  \\ x=-6 \ \vee \ x=6 \\  \\ x\in (-\infty,-6 ) \ \cup \ (6,+\infty)
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2 years ago
May someone pls assist me on this question
Arada [10]

Answer:

x=-4 or x=-8

Step-by-step explanation:

I think those are correct. Pls let me know if they are wrong.

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1 year ago
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A toy rocket is launched from a platform that is 48 ft high. The rocket height above the ground is modeled by h=-16t^2+32t+48. a
Komok [63]

Answer:

a) 64 feet

b)  3 seconds

Step-by-step explanation:

a)

The maximum height of h=h(t) can be bound by finding the y-coordinate of the vertex of y=-16x^2+32x+48.

Compare this equation to y=ax^2+bx+c to find the values of a,b,\text{ and } c.

a=-16

b=32

c=48.

The x-coordinate of the vertex can be found by evaluating:

\frac{-b}{2a}=\frac{-32}{2(-16)

\frac{-b}{2a}=\frac{-32}{-32}

\frac{-b}{2a}=1

So the x-coordinate of the vertex is 1.

The y-coordinate can be found be evaluating y=-16x^2+32x+48 at x=1:

y=-16(1)^2+32(1)+48

y=-16+32+48

y=16+48

y=64

So the maximum height of the rocket is 64 ft high.

b)

When the rocket hit's the ground the height that the rocket will be from the ground is 0 ft.

So we are trying to find the second t such that:

0=-16t^2+32t+48

I'm going to divide both sides by -16:

0=t^2-2t-3

Now we need to find two numbers that multiply to be -3 and add to be -2.

Those numbers are -3 and 1 since (-3)(1)=-3 and (-3)+(1)=-2.

0=(t-3)(t+1)

This implies we have either t-3=0 or t+1=0

The first equation can be solved by adding 3 on both sides: t=3.

The second equation can be solved by subtracting 1 on both sides: t=-1.

So when t=3 seconds, is when the rocket has hit the ground.

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3 years ago
If y=2x-3 find the value of y when x=2
Evgesh-ka [11]
Y = 2x - 3
Y = 2(2) - 3
Y = 4 - 3
Y = 1.

The y value or y coordinate is 1.
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