Answer:
arc ABC = 196°
∠DCQ = 47°
Step-by-step explanation:
arc AD = 70°
∠D = 1/2 arc ABC = 98°
arc ABC = 98° * 2 = 196°
arc CD = 360° - arc AD - arc ABC = 360°-70°-196° = 94°
tangent chord angle DCQ = 1/2 arc CD = 1/2 * 94° = 47°
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
Answer:
y=-x+6
Step-by-step explanation:
make it into y=mx+b form
x+y=6
-x -x
y=-x+6
U did them right but u erased them
