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VashaNatasha [74]

2 years ago

5

A teacher randomly selects one student from a group of students. Fourteen students are wearing a black shirt, six students are w

earing a red shirt, and nine students are wearing a blue shirt. What is the probability that the selected student is wearing a black shirt?

1 answer:

Vera_Pavlovna [14]2 years ago

6 0

Answer:

14/29

Step-by-step explanation:

14/29 is the answer

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sergey [27]

Well lets say M=Melvin's weight and B=two boys the ratio would be M:B or
M to B. If it was the ratio of the two boys to Melvin's weight it would be B:M or B to M. Hope that helped!!☺

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What is -0.5 repeating as a fraction

Eva8 [605]

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3 years ago

If x + y = 4 and x2 − y2 = 64, what is the value of (x − y)?

murzikaleks [220]

The value of (x-y) is 16

Further explanation:

We have to use the given values to find the value

Given

$x+y=4\\and\\x^2-y^2=64$

We will use:

$x^2-y^2=64$

Simplifying by using: $x^2-y^2=(x+y)(x-y)$

So,

$(x+y)(x-y)=64$

As we know that x+y=4

Putting the value in equation

$(4)(x-y)=64$

Dividing both sides by 4

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The value of (x-y) is 16

Keywords: Algebraic formulas, Simplification

Learn more about algebraic expressions at:

#LearnwithBrainly

7 0

3 years ago

the formula for the volume of a cone is v=1/3 pi times r squared h where v represents the volume, r represents the radius of the

Igoryamba

The formula for the volume of a cone is v=1/3 pi times r squared h where v represents the volume, r represents the radius of the base, and h represents the height. what is the height of a cone with a volume of 66 cubic centimeters and a base with radius of 3 centimeters

3 0

3 years ago

Select the two values of x that are roots of this equation

Jet001 [13]

<h2>Hello!</h2>

The answers are:

B. $\frac{-3-\sqrt{29}}{2}$

C. $\frac{-3+\sqrt{29}}{2}$

<h2>Why?</h2>

We can use the quadratic equation to find the two values of x that are roots of the given equation. We must remember that most of the quadratic equations have two roots, however, we could find quadratic equations with just one root or even with no roots, at least in the real numbers.

Quadratic equation:

$\frac{-b+-\sqrt{b^{2}-4ac} }{2a}$

So,

From the given equation we have:

$a=1\\b=3\\c=-5$

Substituting it into the quadratic equation to find the roots, we have:

$\frac{-b+-\sqrt{b^{2}-4ac} }{2a}=\frac{-3+-\sqrt{3^{2}-4*1*-5} }{2*1}\\\\\frac{-3+-\sqrt{3^{2}-4*1*-5} }{2*1}=\frac{-3+-\sqrt{9+20} }{2}\\\\\frac{-3+-\sqrt{29}}{2}$

So,

$x_{1}=\frac{-3-\sqrt{29}}{2}\\\\x_{2}=\frac{-3+\sqrt{29}}{2}$

Hence, the correct options are B and C.

7 0

3 years ago