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mezya [45]
2 years ago
8

The sequence consisting of all natural numbers from 25 to 999 is given as follows.

Mathematics
1 answer:
timama [110]2 years ago
7 0

Answer:

26 28 and 30

Step-by-step explanation:

we already have the first two as 26 and 28

third = a+5d

= 25+5

=30

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Identify the diameter of the disc
Olegator [25]

radius = (4*10^2 + 24^2)/8*10 =

(400 + 576)/80=

976/80 = 12.2

diameter = 12.2 x 2 = 24.4

4 0
3 years ago
3. Mrs Green bakes muffins.
Sphinxa [80]

Answer:

85%

Step-by-step explanation:

Monday:

200 x 0.70 = 140

200 - 140 = 60

Tuesday:

400 x ? = 60

400 x 0.85 = 340

400 - 340 = 60

8 0
3 years ago
You have a coupon for $5 off your total bill at Mama's Meals on Main a. How much will you pay after using the coupon if your bil
HACTEHA [7]

Answer :

(a) Amount paid after using the coupon = $b - $5 = $(b-5)

(b) Amount paid = $23.45 - $5 = $(23.45-5) = $18.45

Amount paid = $54.83- $5 = $(54.83-5) = $49.83

Step-by-step explanation :

As we are given that:

Amount of coupon = $5

If amount of total bill = $b

Now we have to calculate the amount paid after using the coupon.

Amount paid after using the coupon = Total amount of bill - Amount of coupon

Amount paid after using the coupon = $b - $5 = $(b-5)

Now we have to calculate the amount paid if bill was $23.45.

Amount paid after using the coupon = Total amount of bill - Amount of coupon

Amount paid = $23.45 - $5 = $(23.45-5) = $18.45

Now we have to calculate the amount paid if bill was $54.83.

Amount paid after using the coupon = Total amount of bill - Amount of coupon

Amount paid = $54.83- $5 = $(54.83-5) = $49.83

6 0
3 years ago
What is the greatest common factor between 72 and 54?
Elanso [62]
The greatest common factor between 72 and 54 is 18.
3 0
3 years ago
A cable television compan is laying cable in an area with underground utilities. Two subdivisions are located on opposite sides
Schach [20]

Answer:

Step-by-step explanation:

Given:

Point Q = Q is on the north bank 1200 m east of P $40/m to lay cable underground and $80/m way to lay the cable.

Lets denote T be a point on north bank, therefore, point T is t m east and 100m north of P.

Note that 0 < t < 1200

Distance from P to T using Pythagoras theorem:

PT^2 = PQ^2 + QT^2

PT = √(t²+100²) = √(t²+10,000)

Distance from T to Q:

TQ = 1200 - t

From above, Cable from P to T is underwater, and costs $80/m to lay.

Cable from T to Q is underground, and costs $40/m to lay.

Total cost of the cable:

C(t) = 80√(t²+10,000) + 40(1200 - t)

Cost is at its minimum: when dC/dt = C'(t) = 0 and d^2C/dt^2 = C''(t) > 0

dC/dt = C'(t)

= 80 * 1/2 (t² + 10,000)^(-1/2) × 2t + 40 × (-1)

dC/dt = C'(t)

= 80t/√(t² + 10,000) - 40 = 0

80t/√(t² + 10,000) = 40

80t = 40√(t² + 10,000)

2t = √(t² + 10,000)

square both sides:

4t² = t² + 10,000

3t² = 10,000

t² = 10,000/3

t = 100/√3

≈ 57.735

d^2C/dt^2 =

C''(t) = [80√(t² + 10,000) - 80t × t/√(t²+10,000)] /√(t²+10,000)

C''(t) = [(80(t²+10,000) - 80t²) / √(t²+10,000)] /√(t²+10,000)

C''(t) = 800,000 / (t² + 10,000)^(3/2)

C''(t) > 0 for all t

Therefore C(t) is minimized at t = 100/√3

C(100/√3) = 80√(10,000/3 + 10,000) + 40 × (1200 - 100/√3)

= 80 √(40,000/3) + 48,000 - 4000/√3

= 16000/√3 + 48,000 - 4000/√3

= 48,000 + 12,000/√3

= 48,000 + 4,000√3

= 4000 (12 + √3)

≈ 54,928.20

Minimum cost is $54,928.20

This occurs when cable is laid underwater from point P to point T(57.735 m east and 100m north of P) and then underground from point T to point Q (1200 - 57.735)

= 1142.265 m

5 0
3 years ago
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