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VMariaS [17]
3 years ago
15

If x + y = 4 and x2 − y2 = 64, what is the value of (x − y)?

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

The value of (x-y) is 16

Further explanation:

We have to use the given values to find the value

Given

x+y=4\\and\\x^2-y^2=64

We will use:

x^2-y^2=64

Simplifying by using: x^2-y^2=(x+y)(x-y)

So,

(x+y)(x-y)=64

As we know that x+y=4

Putting the value in equation

(4)(x-y)=64

Dividing both sides by 4

\frac{4(x-y)}{4}=\frac{64}{4}\\x-y=16

The value of (x-y) is 16

Keywords: Algebraic formulas, Simplification

Learn more about algebraic expressions at:

  • brainly.com/question/10879401
  • brainly.com/question/10940255

#LearnwithBrainly

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Solve for m &lt; L
s2008m [1.1K]

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<h3>What is trigonometry?</h3>

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The right-angle triangle is given below.

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More about the trigonometry link is given below.

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Find the volume of a cone with a height of 3.25 centimeters and<br> a diameter of 2.2 centimeters.
saveliy_v [14]

Answer:

As per Provided Information

Height of cone h is 3.25 cm

Diameter of cone is 2.2 cm

  • Radius = Diameter/2

Radius = 2.2/2

Radius = 1.1 cm

We have been asked to determine the volume of the cone .

<u>Using </u><u>Formulae </u>

\boxed{\bf \:Volume_{(Cone)}  =  \cfrac{1}{3}  \pi {r}^{2}h}

Substituting the given value and let's solve it

\sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{1}{3}  \times 3.14 \times  {1.1}^{2}  \times 3.25 \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{1}{3}  \times 3.14 \times 1.21 \times 3.25 \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{1}{3}  \times 3.14 \times 3.9325 \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{1}{3}  \times 12.34805 \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{12.34805}{3}  \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  = 4.11 {cm}^{3}

<u>Therefore</u><u>,</u>

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kupik [55]

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