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2 years ago

The pieces of ice float on water why

Physics

1 answer:

irga5000 [103]2 years ago

4 0

they float on water because the ice has the same mass of water and is density is lighter

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What would happen if the Earth stopped rotating?

trapecia [35]

Answer:

the atmosphere would still be in motion with the Earth's original 1100 mile per hour rotation speed at the equator. ... This means rocks, topsoil, trees, buildings, your pet dog, and so on, would be swept away into the atmosphere.

Explanation:

to me, this means we would proabaly be sucked into outer space and could die if no astronaut gear is on

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3 years ago

Un adolescente que va en monopatín rueda hacia abajo sobre un plano inclinado de 18.0 m de largo. El chico parte con una rapidez

qaws [65]

Answer: 31.62°

Explanation:

Tenemos como datos:

Distancia = 18.0m

Velocidad inicial = 2.0 m/s

Tiempo total = 3.3s

Sabemos que para un plano inclinado (ignorando el rozamiento) la aceleración se escribe como:

a(t) = g*sen(θ)

donde θ es el ángulo del plano inclinado, y g = 9.8m/s^2

Sabemos que para la velocidad tenemos que integrar la aceleración sobre el tiempo, entonces:

v(t) = g*sen(θ)*t + v0

Donde v0 es la velocidad inicial: v0 = 2.0m/s

v(t) = 9.8m/s^2*sen(θ)*t + 2.0m/s

Y para la posición, podemos integrar de vuelta sobre el tiempo:

p(t) = 0.5*9.8m/s^2*sen(θ)*t^2 + 2.0m/s*t + p0

Donde p0 es la posición inicial, podemos considerar que es cero para este problema.

p(t) = 4.9m/s^2*sen(θ)*t^2 + 2.0m/s*t

Y usando los datos iniciales, sabemos que en 3.3 segundos se recorren 18 metros, entonces:

p(3.3s) = 18m = 4.9m/s^2*sen(θ)*(3.3s)^2 + 2.0m/s*3.3s

18m = 51.744m*sen(θ) + 6.6m

sen(θ) = (18m - 6.6m)/ 51.744m

θ = cosec( (18m - 6.6m)/ 51.744m ) = 31.62°

4 0

3 years ago

If you are running at the speed of sound, would you still be able to hear the music in your headphones?

Alex Ar [27]

Ask Barry Allen he’s the faster man alive

4 0

3 years ago

g (a) Calculate the speed of a proton that is accelerated from rest through a potential difference of 127 V. km/s (b) Calculate

Kisachek [45]

Answer:

Explanation:

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3 years ago

A 0.50 kilogram ball is held at a height of 20 meters. What is the kinetic energy of the ball when it reaches halfway after bein

Elis [28]

Answer:

A. 49 joules

Step By Step Solution:

Via kinematic equations we can must first determine the velocity of this object after 10 meters (since halfway of 20 meters is 10).

$v_{final}^2=v_{initial}^2+2gd$

Where the initial velocity is zero since it's held at a height of 20 meters, hence it's not moving initially, g is the average gravity on Earth 9.8 m/s^2 and d is the distance this object will travel so 10 meters. By plugging these values in we obtain:

$v_{final}^2=0+2(9.8)(10)\\\\v_{final}=\sqrt{2(9.8)(10)}=14m/s$

And the equation for kinetic energy is :

$K.E.=\frac{1}{2}mv^2=\frac{1}{2}(0.5kg)(14m/s)^2=49J$

So the kinetic energy halfway after being released is 49 joules.

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3 years ago

The pieces of ice float on water why​

The pieces of ice float on water why