During Physical Change there would be a re-arrangements of atoms or molecules, changes of the arrangement may be change in the distance between atoms or molecules, change in the crystal form, .....etc
for example: water when heated it undergoes a Physical Change and turn into vapor, this means the heat cause the distance between water molecules to increase, so it transferred from the liquid form to the gas form.
NOTE that in Physical Change there is no change in the chemical structure and the material retains all its chemical properties, and no new compounds are produced.
again, A physical change is any change not involving a change in the substance's chemical identity. Matter undergoes chemical change when the composition of the substances changes: one or more substances combine or break up (as in a relationship) to form new substances.Physical changes occur when objects undergo a change that does not change their chemical nature. A physical change involves a change in physical properties. Physical properties can be observed without changing the type of matter. Examples of physical properties include: texture, shape, size, color, odor, volume, mass, weight, and density.
BUT in Chemical Change ( or Chemical Reaction ) there would be change in the chemical nature of the material undergoing a Chemical Change with the production of new compounds.
Answer:
C
Explanation:
Usually when you are at the bottom you are at peak speed. It also shows that Kinetic Energy is the green bar and in picture C the green bar is highest.
Explanation:
Charges,![q_1=8\ \mu C=8\times 10^{-6}\ C](https://tex.z-dn.net/?f=q_1%3D8%5C%20%5Cmu%20C%3D8%5Ctimes%2010%5E%7B-6%7D%5C%20C)
![q_2=-5\ \mu C=-5\times 10^{-6}\ C](https://tex.z-dn.net/?f=q_2%3D-5%5C%20%5Cmu%20C%3D-5%5Ctimes%2010%5E%7B-6%7D%5C%20C)
The distance between charges, r = 10 cm = 0.1 m
We need to find the magnitude and direction of the electric force. It is given by :
![F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\\\F=36\ N](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bkq_1q_2%7D%7Br%5E2%7D%5C%5C%5C%5CF%3D%5Cdfrac%7B9%5Ctimes%2010%5E9%5Ctimes%208%5Ctimes%2010%5E%7B-6%7D%5Ctimes%205%5Ctimes%2010%5E%7B-6%7D%7D%7B%280.1%29%5E2%7D%5C%5C%5C%5CF%3D36%5C%20N)
So, the required force between charges is 36 N and it is towards positive charge i.e. +8 μC.
B) not work ,because the water would freeze
Answer:
114.86%
Explanation:
In both cases, there is a vertical force equal to the sprinter's weight:
Fy = mg
When running in a circle, there is an additional centripetal force:
Fx = mv²/r
The net force is found with Pythagorean theorem:
F² = Fx² + Fy²
F² = (mv²/r)² + (mg)²
F² = m² ((v²/r)² + g²)
F = m √((v²/r)² + g²)
Compared to just the vertical force:
F / Fy
m √((v²/r)² + g²) / mg
√((v²/r)² + g²) / g
Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:
√((12²/26)² + 9.8²) / 9.8
1.1486
The force is about 114.86% greater (round as needed).