A man is heterozygous ( Cc ) for a recessive trait that causes a fatal illness , the mother does not carry the recessive allele

Question

2 years ago

13

( CC ) . What is the percentage chance of their children being a carrier the trait ?
A.50%
B.25%
C.75%
D.0%

2 answers:

lorasvet [3.4K] · Answer 1 · 2023-02-26T02:31:44+03:00

7 0

50% using a punnet square

Artemon [7] · Answer 2 · 2023-02-26T01:02:32+03:00

5 0

Answer: A. 50%

Explanation: If you create a Punnett Square and cross the 2 genotypes, out of the 4 possibilities, 2 will be CC and 2 will be Cc.