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Scorpion4ik [409]
3 years ago
11

For each solute identify the better solvent: water or carbon tetrachloride Na2, I2, CCH2O, C6H6

Chemistry
1 answer:
Virty [35]3 years ago
3 0
NH3 = water (it is actually a water soluble gas)
C6H14 = CCl4 (C6H14 won't mix with water at all)
Na2S = water (Na2S is a salt. Salts dissolve best in water)
Br2 = CCl4, but it will also dissolve in water.
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Samira has a son who is 24 months old. Her sister Paulina also has a son who is one and a half years old. Whose son is older? Ex
Troyanec [42]
Samira’s son is older because there are 12 months in a year and we can gather that 12+12=24 so we know that Paulina’s son is younger because he is only 18 months.
8 0
3 years ago
Read 2 more answers
Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
4 years ago
Gaseous BF3 and BCl3 are mixed in equal molar amounts. All B-F bonds have about the same bond enthalpy, as do all B-Cl bonds. Co
lord [1]

Solution :

$BF_3 (g) + BCl_3 (g) \rightarrow BF_2 Cl + BCl_F(g)$

<u>Explanation 1 </u>:

Spontaneity of the reaction is based on two factors :

-- the tendency to acquire a state of minimum energy

-- the energy of a system to acquire a maximum randomness.

Now, since there isn't much difference in the bond enthalpies of B-F and B-Cl. So, we can say the major driving factor is tendency to acquire a state of maximum randomness.

<u>Explanation 2 </u>:

A system containing the \text{"chemically mixed"} B halides has a \text{greater entropy} than a system of $BCl_3$ and BF_3.

It has the same number of \text{gas phase molecules}, but more distinguishable kinds of \text{molecules}, hence, more microstates and higher entropy.

8 0
3 years ago
Which of these are equal to 3.01 x 1023 particles 76.9 g of diatomic iodine (I2) 79.9 g of diatomic bromine (Br2) 6 g of carbon
solmaris [256]
To determine which is the correct answer, we convert the mass of the compounds into units of particles of the compound. We use the molar masses and the Avogadro's number. We do as follows:

<span>76.9 g I2  (1 mol / 253.81 g) (6.022x10^23 particles / 1 mol ) = 1.82x10^23

79.9 g Br2 (1 mol / 159.81 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>

6 g C (1 mol / 12 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>

13.01 g CH4 ( 1 mol / 16.04 g )</span>(6.022x10^23 particles / 1 mol ) = 4.88x10^23 particles

Therefore, the answers are Br2 and C.
3 0
3 years ago
6 NaOH + 2 Al --&gt; 2 Na3AlO3 + 3 H2 If you start with 258 g of Al, how many moles of Na3AlO3 can you make?
tatyana61 [14]

Solution :

Assuming all Al will be consumed in the reaction.

From the given equation, 2 mole of Al produce 2 mole of Na_3AlO_3.

So, 1 mole of Al produce 1 mole of  Na_3AlO_3.     .....statement 1)

Number of moles of Al in 258 gram of Al.

n = \dfrac{mass}{molar\ mass}\\\\n = \dfrac{258}{27}\ moles\\\\n = 9.556 \ moles

Therefore, from statement 1) number of moles of Na_3AlO_3 produced is also 9.556 moles.

7 0
3 years ago
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