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Alex787 [66]
3 years ago
12

Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io

n in the solution? Explain.
Chemistry
1 answer:
Lera25 [3.4K]3 years ago
3 0

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

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Answer:

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Explanation:

Given

T_1 = 25.2^oC

T_2 = 55.1^oC

m = 5.00g

\triangle Q= 133J

<em>See attachment for chart</em>

Required

Identify the unknown substance

To do this, we simply calculate the specific heat capacity from the given parameters using:

c = \frac{\triangle Q}{m\triangle T}

This gives:

c = \frac{\triangle Q}{m(T_2 - T_1)}

So, we have:

c = \frac{133J}{5.00g * (55.1C - 25.2C)}

c = \frac{133J}{5.00g * 29.9C}

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c = 0.89\ J/gC

From the attached chart, we have:

Al(s) = 0.89\ J/gC --- The specific heat capacity of Aluminum

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3 years ago
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kotegsom [21]

Answer:

you

Explanation:

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7 0
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When a gas is cooled at constant pressure, what happens to its molecules and volume?
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tatuchka [14]

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Explanation:

Copper (ii) oxide has the chemical formula CuO.

Now given that:

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Z = 79.5 g/mol x 2.00 moles

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