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OverLord2011 [107]
3 years ago
8

Write the pair of fractions 1/4 and 1/6 as a pair of fractions with a common denominator

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer: 1/4 = 3/12 , 1/6 = 2/12

Step-by-step explanation:

<em>To find equivalent fractions with a common denominator, we have to calculate the least common multiple of the denominators which is called the Least Common Denominator (</em><em>LCD</em><em>). </em>

<em>First we have to list the prime factors of each denominator:</em>

4: 2 x 2

6: 2 x 3

<em>Then we have to multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, we  multiply the factor the greatest number of times it occurs. </em>

2: two occurrences

3: one occurrence

LCM(4,6) = 2 x 2 x 3 = 12 ◄LCD

<em>Now we can find equivalent fractions with this LCD .</em>

<em>For each fraction, we have to determine the number needed to multiply the denominator to get the LCD. Then have to multiply both the numerator and denominator by that number: </em>

<h3><em>LCD = 12</em></h3><h3>1/4 </h3>

LCD/4 = 12/4 = 3

1/4 = 3x1/3x4 = 3/12

<h3>1/6 </h3>

LCD/6 = 12/6 = 2

1/6 = 2x1/2x6 = 2/12

Answer: 1/4 = 3/12 , 1/6 = 2/12

<h2><em>Spymore</em></h2>
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Answer:

SI=PTR/100

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3 years ago
Assume that females have pulse rates that are normally distributed with a mean of u = 75.0 beats per minute and a standard devia
Elan Coil [88]

Answer:

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 75, \sigma = 12.5

Find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

This is the pvalue of Z when X = 81 subtracted by the pvalue of Z when X = 69.

X = 81

Z = \frac{X - \mu}{\sigma}

Z = \frac{81 - 75}{12.5}

Z = 0.48

Z = 0.48 has a pvalue of 0.6844

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 75}{12.5}

Z = -0.48

Z = -0.48 has a pvalue of 0.3156

0.6844 - 0.3156 = 0.3688

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

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4 years ago
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Given function :-

\bf \implies g(x) = \dfrac{3}{x}+7

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\bf \implies y = \dfrac{3}{x}+7

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\bf \implies x = \dfrac{3}{y}+7

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\bf\implies \dfrac{3}{y}= x -7 \\\\\bf\implies y =\dfrac{3}{x-7}

  • Replace y with f-¹(x) .

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